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Ronch [10]
3 years ago
14

What is the linear equation for (6,3) with a slope of 0

Mathematics
2 answers:
Vlada [557]3 years ago
8 0
Answer: linear equation
Y = 3
Gre4nikov [31]3 years ago
8 0

Answer:

y = 3

Because y = 0x+3

Step-by-step explanation:

when slope is 0 we take the y intercept

and show y = 0x+C

We draw 0 as horizontal on line y = 3

and then we find our 2nd point (0.3) and given point ( 6.3)

y = 0x + 3

We can also show formula for full workings

y-y1 = y1(x+x1)

y - 3 = -3 (0) + 6

y-3+3 =  0 - 18 + 3

y = 0x - 15

y = -15 / -7  the (x- 6)^2 + ( x+3)^2 = -36 / 9 = -4

- 4 - 3 = -7

y =  0x - 15/-7

y =  0x - 3

y = 3

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Answer:

x = 2 csc(1) y - π/4

Step-by-step explanation:

Solve for x:

y = 1/2 sin(1) (x + π/4)

y = 1/2 (x + π/4) sin(1) is equivalent to 1/2 (x + π/4) sin(1) = y:

1/2 sin(1) (x + π/4) = y

Divide both sides by sin(1)/2:

x + π/4 = 2 csc(1) y

Subtract π/4 from both sides:

Answer:  x = 2 csc(1) y - π/4

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Answer:

a) = 4.5

b) = 3.3

Step-by-step explanation:

Before solving our problems given to us let us under stand the rule of cube roots

It says \sqrt[3]{x \times x \times x} = x   -----(A)

Also

\sqrt[3]{x \times x \times x \times y \times y \times y} = x \times y   ---(B)

Now let us see each part one by one

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Now 64 = 4 x 4 x 4

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0.008 = 0.2 x 0.2 x 0.2

substituting these values

\sqrt[3]{4 \times 4 \times 4} + \sqrt[3]{0.3 \times 0.3 \times 0.3} + \sqrt[3]{0.2 \times 0.2 \times 0.2}

Applying Rule A in above

=4+0.3+0.2

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