Answer:
Given that,
The number of grams A of a certain radioactive substance present at time, in years
from the present, t is given by the formula

a) To find the initial amount of this substance
At t=0, we get


We know that e^0=1 ( anything to the power zero is 1)
we get,

The initial amount of the substance is 45 grams
b)To find thehalf-life of this substance
To find t when the substance becames half the amount.
A=45/2
Substitute this we get,


Taking natural logarithm on both sides we get,







Half-life of this substance is 154.02
c) To find the amount of substance will be present around in 2500 years
Put t=2500
we get,




The amount of substance will be present around in 2500 years is 0.000585 grams
Y intercept is -6
Y= 5x^2-X-6
Y= 5(0)^2-0-6
Y= 0-0-6
Answer:
4 to 1
Step-by-step explanation:
The greatest common factor between 8 and 2 is 2. So 2 will go into 8, 4 times. And 2 will go into 2, 1 time. So simplified the equivalent ratio is 4:1.
Step-by-step explanation:
the formula to calculate a circumference is

(consider x as the diameter)
so I'll be noting the circumference as C alongside the circle's ranking
a.

b.

c.

hope I helped
Answer:
no solution
Step-by-step explanation:
n -8 = 6+n
Subtract n from each side
n-n -8 = 6+n-n
-8 = 6
This is never true so there is no solution