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3 years ago

carol spends 18 hours in a 2-week period practicing her culinary skills. how many hours does she spend in 5 weeks

Mathematics

1 answer:

Dovator [93]3 years ago

8 0

Answer:

She spends 45 hours practicing her culinary skills in 5 weeks.

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Lin is shopping for a couch with her dad and hears him ask the salesperson, “How much is your commission?” The salesperson says

Natali5045456 [20]

Answer:

Step-by-step explanation:

The answer is $27.23 for the commission

Work out problem:

495×5.5%=27.225

So you round that off to 27.23

When working with a problem with percentages, you always multiple to figure out how you got your and what is your answer.

4 0

3 years ago

A team of runners is needed to run a 1/4 -mile relay race. If each runner must run

Sveta_85 [38]

Answer:

4 runners

Step-by-step explanation:

I divided 1/4 by 1/16 and got 4 as an answer.

Hope this helps :)

(Correct me if i am wrong)

8 0

4 years ago

Read 2 more answers

The life, in years, of a certain type of electrical switch has an exponential distribution with an average life β=44. If 100 o

Bond [772]

Answer:

0.9999

Step-by-step explanation:

Let X be the random variable that measures the time that a switch will survive.

If X has an exponential distribution with an average life β=44, then the probability that a switch will survive less than n years is given by

$\bf P(X$

So, the probability that a switch fails in the first year is

$\bf P(X$

Now we have 100 of these switches installed in different systems, and let Y be the random variable that measures the the probability that exactly k switches will fail in the first year.

Y can be modeled with a binomial distribution where the probability of “success” (failure of a switch) equals 0.0225 and

$\bf P(Y=k)=\binom{100}{k}(0.02247)^k(1-0.02247)^{100-k}$

where

$\bf \binom{100}{k}$ equals combinations of 100 taken k at a time.

The probability that at most 15 fail during the first year is

$\bf \sum_{k=0}^{15}\binom{100}{k}(0.02247)^k(1-0.02247)^{100-k}=0.9999$

3 0

3 years ago

Prove that if a and b are nonzero integers, a divides b, and a b is odd, then a is odd.

hammer [34]

It is proved that the if a and b are nonzero integers, a divides b, and a b is odd, then a is odd.

According to the statement

we have to prove that the if a and b are nonzero integers, a divides b, and a b is odd, then a is odd.

And for this proof we use the contradiction

So,

Proof by contradiction is a common proof technique that is based on a very simple principle: something that leads to a contradiction can not be true, and if so, the opposite must be true.

So for this purpose,

Assume a is even, so a = 2k for some integer k. Now let a and b be integers such that a divides b and a + b is odd.

Since a divides b, b = an for integer n, and in turn b = 2nk, which means b is even and hence a + b is also even. But this contradicts our initial assumption, so a must be odd.

So, It is proved that the if a and b are nonzero integers, a divides b, and a b is odd, then a is odd.

Learn more about integers here

brainly.com/question/17695139

#SPJ4

7 0

2 years ago

Select all the expressions that are equivalent to -36x + 54y - 90.

adelina 88 [10]

Answer:

-18(2x-3y+5)

-2(18x-27y+45)

5 0

3 years ago