Answer:
z= 3.63
z for significance level = 0.05 is ± 1.645
Step-by-step explanation:
Here p = 42% = 0.42
n= 500
We formulate our null and alternative hypotheses as
H0: p= 0.42 against Ha : p> 0.42 One tailed test
From this we can find q which is equal to 1-p= 1-0.42 = 0.58
Taking p`= 0.5
Now using the z test
z= p`- p/ √p(1-p)/n
Putting the values
z= 0.5- 0.42/ √0.42*0.58/500
z= 0.5- 0.42/ 0.0220
z= 3.63
For one tailed test the value of z for significance level = 0.05 is ± 1.645
Since the calculated value does not fall in the critical region we reject our null hypothesis and accept the alternative hypothesis that more than 42% people owned cats.
<span>(-45 + (-12) / 2 = -28.5
</span>So the answer is -28.5
Solve x by simplifying both sides of the equation & then isolating the variable x=-4 & the negative comes in from the -12
8 = letter
c = vowels
8 -c = consonants
_____________
c = 3
so, you've got three vowels
So 1 head per squirel and 1 head per bird
4 legs per squirel and 2 legs per bird
s=number of squirels
b=birds
the equatinos should be
1b+1s=number of heads=16
and
2b+4s=number of legs=44
(note 2b=2 times b)
so we aolve
b+s=16 and 2b+4s=44
simplify the second equaiton by divideinb by 2
2b+4s=44
divide 2
b+2s=22
b+s=16
and
b+2s=22
we can actually add the two equations together with the first one made negative
-b-s=-16
<u>b+2s=22+</u>
0b+1s=6
s=6
subsitute
b+s=16
b+6=16
subtract 6 from both sides
b=10
10 birds
answer is c
