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viktelen [127]
3 years ago
15

Help Help Help Help Help

Mathematics
2 answers:
Likurg_2 [28]3 years ago
5 0

Answer:

1.92

Step-by-step explanation:

multipy 8 by .08 to get the sales tax amount

to find the total cost (if you need it) add the sales tax to the original cost

hope it helps

Mazyrski [523]3 years ago
3 0

Answer:

1.92

Step-by-step explanation:   niueikieoewdn4u

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The conclusion is there is likely an association between the categorical variables because the sum of the relative frequencies is 1. 0.

<h3>What is the true statement?</h3>

Categorical variables are variables that can only take on a fixed number of values. An example of categorical variables is gender. One can either be a male or a female.

The sum of the categorical variables is 1. This indicates that the two variables are negatively correlated. It means that someone would be either pick one of the variables.

To learn more about categorical variables, please check: brainly.com/question/27763755

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7 0
2 years ago
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Makovka662 [10]
The person above me is incorrect.
ANSWER: -77 5/8
6 0
3 years ago
Can you guys answer this
emmasim [6.3K]

Answer:

y=10x

Step-by-step explanation:

because it's going up by 10 each time

5 0
3 years ago
Read 2 more answers
On any given day, the probability that a large local river is polluted by carbon tetrachloride is 0.12. Each day, a test is cond
babymother [125]

Answer:

a) 0.2416

b) 0.4172

c) 0.0253

Step-by-step explanation:

Since the result of the test should be independent of the time , then the that the test number of times that test proves correct is independent of the days the river is correct .

denoting event a A=the test proves correct and B=the river is polluted

a) the test indicates pollution when

- the river is polluted and the test is correct

- the river is not polluted and the test fails

then

P(test indicates pollution)= P(A)*P(B)+ (1-P(A))*(1-P(B)) = 0.12*0.84+0.88*0.16 = 0.2416

b) according to Bayes

P(A∩B)= P(A/B)*P(B) → P(A/B)=P(A∩B)/P(B)

then

P(pollution exists/test indicates pollution)=P(A∩B)/P(B) = 0.84*0.12 / 0.2416 = 0.4172

c) since

P(test indicates no pollution)= P(A)*(1-P(B))+ (1-P(A))*P(B) = 0.84*0.88+  0.16*0.12 = 0.7584

the rate of false positives is

P(river is polluted/test indicates no pollution) = 0.12*0.16 / 0.7584 = 0.0253

4 0
3 years ago
How do you get the answer? <br> Show your work. Please!
katen-ka-za [31]
Okie, hope you a new year!

4 0
4 years ago
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