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nikklg [1K]
3 years ago
10

3 x 10 + 2 x 1 + 6 x 1|100 + 4 x 1|1,000 is the expanded form of which decimal?​

Mathematics
1 answer:
Arisa [49]3 years ago
4 0

Answer:

6 × 1 + 3 ×(1/100) + 9 × 10 + 2 × (1/10)

We know that 1, 1/100, 10, and 1/10 are place values. We can write 14.25 as 1 × 10 + 4 × 1 + 2 × (1/10) + 5 × (1/100), for example. We can use that information to solve the above.

We also can multiply and add the expression.

6 × 1 + 3 ×(1/100) + 9 × 10 + 2 × (1/10)

6 + 3/100 + 90 + 2/10

6 + 0.03 + 90 + 0.2

96.23

Step-by-step explanation:

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Answer:

(7, 0) and (-5, 0)

Step-by-step explanation:

<u>Vertex form</u>

y=a(x-h)^2+k  

(where (h, k) is the vertex)

Given:

  • vertex = (1, -108)

\implies y=a(x-1)^2-108

Given:

  • y-intercept = (0, -105)

\implies a(0-1)^2-108=-105

\implies a(-1)^2=-105+108

\implies a=3

Therefore:

\implies y=3(x-1)^2-108

The x-intercepts are when y = 0

\implies 3(x-1)^2-108=0

\implies 3(x-1)^2=108

\implies (x-1)^2=36

\implies x-1=\pm \sqrt{36}

\implies x=1\pm 6

\implies x=7, x=-5

Therefore, the x-intercepts are (7, 0) and (-5, 0)

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