Answer: A 24 cm piece of string is cut into two pieces , one piece is used to form a circle and the other piece is used to form a square.
How should this string be cut so that the sum of the areas is a minimum .
:
Let x = the circumference of the circle
then
(24-x) = the perimeter of the square
:
Find the area of the circle
find r
2*pi*r = x
r =
Find the area of the circle
A =
A =
A = sq/cm, the area of the circle
:
Find the area of the square
A = sq/cm the area of the square
The total area
At = +
Graph this equation, find the min
Min occurs when x=10.6 cm
cut string 10.6 cm from one end
Step-by-step explanation: Hope I help out alot (-: :-)
Answer:
about a half teaspoon
Step-by-step explanation:
ATQ


Now




From all equations




Now
Adding 3 and 4


One side won't be covered hence
Answer:
The graph has a removable discontinuity at x=-2.5 and asymptoe at x=2, and passes through (6,-3)
Step-by-step explanation:
A rational equation is a equation where

where both are polynomials and q(x) can't equal zero.
1. Discovering asymptotes. We need a asymptote at x=2 so we need a binomial factor of

in our denomiator.
So right now we have

2. Removable discontinues. This occurs when we have have the same binomial factor in both the numerator and denomiator.
We can model -2.5 as

So we have as of right now.

Now let see if this passes throught point (6,-3).


So this doesn't pass through -3 so we need another term in the numerator that will make 6,-3 apart of this graph.
If we have a variable r, in the numerator that will make this applicable, we would get

Plug in 6 for the x values.



So our rational equation will be

or

We can prove this by graphing