We're told that
a. We want to find 
. By definition of conditional probability,
By the law of total probability,
Then
(the first equality is Bayes' theorem)
b. We want to find 
.
since 
.
9514 1404 393
Answer:
x ∈ (-∞, 9) U (-1, ∞)
Step-by-step explanation:
Get the absolute value by itself. Do that by multiplying by 4.
|3x +15| > 12
This resolves to two cases:
<u>3x +15 > 12</u>
x +5 > 4 . . . . divide by 3
x > -1 . . . . . . .subtract 5
<u>-(3x +15) > 12</u>
x +5 < -4 . . . . divide by -3
x < -9 . . . . . . . subtract 5
Then the solution in interval notation is ...
x ∈ (-∞, 9) U (-1, ∞)
To put an equation into (x+c)^2, we need to see if the trinomial is a perfect square.
General form of a trinomial: ax^2+bx+c
If c is a perfect square, for example (1)^2=1, 2^2=4, that's a good indicator that it's a perfect square trinomial.
Here, it is, because 1 is a perfect square.
To ensure that it's a perfect square trinomial, let's look at b, which in this case is 2.
It has to be double what c is.
2 is the double of 1, therefore this is a perfect square trinomial.
Knowing this, we can easily put it into the form (x+c)^2.
And the answer is: (x+1)^2.
To do it the long way:
x^2+2x+1
Find 2 numbers that add to 2 and multiply to 1.
They are both 1.
x^2+x+x+1
x(x+1)+1(x+1)
Gather like terms
(x+1)(x+1)
or (x+1)^2.
Answer:
It is 91% more likely that the tree was atmost 500 yards from the river.
<h3>Step-by-step explanation:</h3>
We are given with distance and height of 100 young trees near a river.
From that table, in total there are 55 trees which grow more than 3 ft during the year.
And among those 55 trees, 50 trees are atmost 50 yards from river.
Hence it is ≈91% more likely that the tree was atmost 50 yards from the river.
