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kicyunya [14]
3 years ago
14

Is a triangle whose side measure 12 ft, 16 ft and 20 ft a right triangle?

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
7 0

Answer:

This is a Right Triangle

Step-by-step explanation:

12=a 16=b 20=c

Now lets solve

a^2+b^2=c^2

144+b^2=c^2

144+256=c^2

144+256=400

c^2=400

The square root of 400 is 20..

This IS a Right Triangle

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lozanna [386]
I hope this helps you

6 0
4 years ago
Mark and Tony share a sum of money in the ratio 3:5. What fraction of the money did Tony ratio receive?
gladu [14]
Answer:

Part A is 3/8 of the whole
Part B is 5/8 of the whole

Solution:
Assuming there are no other parts,
the Whole = A + B is the denominator:
Whole = 3 + 5 = 8

Part A = 3 and Part B = 5 are numerators for each fraction.

The fractions are then:
3/8 and 5/8

Meaning:
Part A is 3/8 of the whole
Part B is 5/8 of the whole
4 0
4 years ago
Plz help its so confusing
aleksklad [387]

Answer:

20, 4

Step-by-step explanation:

Let's assume total number of students registered is n

Last week n/4 people are absent

so people present are n - n/4 = <u>3n/4</u>

Today after return of Jen  1/5 n are absent

so people present are n - n/5 = 4n/5

which is also equal to last week present people + 1 (Jen)

= 3n/4 + 1

= (3n + 4) / 4

so (3n + 4) / 4 = 4n/5

=> 3n + 4 = 4n/5 * 4

=> (3n + 4) * 5 = 16n

=> 15n + 20 = 16n

=> 20 = n

=> n = 20

So total students registered for class is 20

today no of people absent = n/5 = 20/5 = 4

8 0
3 years ago
38. Solve the simultaneous equations<br>3x + 4y = 11, x + 6y = 13.<br>​
vitfil [10]

Answer:

<h2>X=1</h2><h2>y=2</h2>

please see the attached picture for full solution..

hope this helps...

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6 0
3 years ago
Read 2 more answers
Question 8 using radians, find the amplitudeand period of each function and graph it
brilliants [131]
Given

The function is given as

y=3cos\frac{\theta}{3}Required

To determine the amplitude and period.

Explanation

The general trigonometric equation is

y=Acos(Bx-C)+D

where A is the amplitude.

Compare with the given equaiton.

A =3.

Then the amplitude is 3.

Now , find the period.

P=\frac{2\pi}{B}

Substitute the value of B in the expression.

P=\frac{2\pi}{(\frac{1}{3})}=6\piAnswer

Hence the amplitude is 3 and period is

6\pi

The graph of the equation is determined as

5 0
2 years ago
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