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3 years ago

Is a triangle whose side measure 12 ft, 16 ft and 20 ft a right triangle?

Mathematics

1 answer:

tensa zangetsu [6.8K]3 years ago

7 0

Answer:

This is a Right Triangle

Step-by-step explanation:

12=a 16=b 20=c

Now lets solve

a^2+b^2=c^2

144+b^2=c^2

144+256=c^2

144+256=400

c^2=400

The square root of 400 is 20..

This IS a Right Triangle

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Find the area of the region under the graph of f on [a, b]. f(x) = x2 − 8x + 17; [−1, 2]

Harman [31]

Answer:

The area is 42 area units.

Step-by-step explanation:

The area of a function f(x) on an interval [a,b] is given by:

$A = \int\limits^a_b {f(x)} \, dx$

Applying to this question:

$A = \int\limits^-1_2 {x^2 - 8x + 17} \, dx$

Then

$F(x) = \frac{x^{3}}{3} - 4x^{2} + 17x$

$A = F(2) - F(-1)$

$F(2) = frac{2^{3}}{3} - 4*2^{2} + 17*2 = \frac{8}{3} + 18 = \frac{8 + 3*18}{3} = \frac{62}[3}$

$F(-1) = frac{(-1)^{3}}{3} - 4*(-1)^{2} + 17*(-1) = -\frac{1}{3} - 21 = \frac{-1 - 21*3}{3} = -\frac{64}[3}$

$A = F(2) - F(-1) = \frac{62}[3} - (-\frac{64}[3}) = \frac{62+64}{3} = 42$

The area is 42 area units.

5 0

3 years ago

Find the angle in the table

yan [13]

Answer:

360/100=3.6

30 x 3.6 = 108

10 x 3.6 = 36

From the 10 you can multiply by 5. 36 x 5 = 180

10 3.6 = 36

36 + 36 = 72. 108 + 72 = 180

180 + 180 = 360.

Angles are Red-108, Blue-36, Green-180, and yellow-36.

Hope this helped

(Don't give me brainliest)

Step-by-step explanation:

4 0

3 years ago

11. Use an inequality symbol (<, >, 2, =) to compare -26

svetlana [45]

Answer:

c. <

Step-by-step explanation:

-26 < (less than) 54

8 0

3 years ago

H function is even, odd, or neither. b. g(x) = x² - 2 Is it odd or even

o-na [289]

$g(x) = x^2 - 2 \text{ is even function }$

Solution:

Given that,

$g(x) = x^2 - 2$

We have to find whether the above function is odd or even

If a function is: y = f(x)

If f(-x) = f(x), the function is even

If f(-x) = - f(x), the function is odd

Which is,

$\mathrm{Even\:Function:\:\:A\:function\:is\:even\:if\:}f\left(-x\right)=f\left(x\right)\mathrm{\:for\:all\:}x\in \mathbb{R}\\\\\mathrm{Odd\:Function:\:\:A\:function\:is\:odd\:if\:}f\left(-x\right)=-f\left(x\right)\mathrm{\:for\:all\:}x\in \mathbb{R}$