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3 years ago

The solution set of IR - 31 = 10 is

Mathematics

1 answer:

Aliun [14]3 years ago

8 0

Answer:

41-31=10

You just add 31 to ten which gives you the total and you subtract by 31 and get 10 idk if that makes since.

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CAN SOMEBODY PLLZZZZ HELP ME WITH THE QUESTION BELOW AND HOW TO SOLVE QUESTIONS LIKE THIS, IM STUDYING FOR A MATH TEST PLLLZZ!!!

andreyandreev [35.5K]

Answer:

$\frac{-10}{9}, \frac{-2}{3}, \frac{4}{6}, \frac{6}{5}, \frac{5}{4}$

I hope this helps!

3 0

3 years ago

Write the equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x

Solnce55 [7]

Answer:

The equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x is $\mathbf{y=-\frac{2}{3}x+3 }$

Step-by-step explanation:

We need to Write the equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x

The equation in slope-intercept form is: $y=mx+b$ where m is slope and b is y-intercept.

Finding Slope:

The both equations given are parallel. So, they have same slope.

Slope of given equation y= - 2/3x is m = -2/3

This equation is in slope-intercept form, comparing with general equation $y=mx+b$ where m is slope , we get the value of m= -2/3

So, slope of required line is: m = -2/3

Finding y-intercept

Using slope m = -2/3 and point (-3,5) we can find y-intercept

$y=mx+b\\5=-\frac{2}{3}(-3)+b\\5=2+b\\ b=5-2\\b=3$

So, we get b = 3

Now, the equation of required line:

having slope m = -2/3 and y-intercept b =3

$y=mx+b\\y=-\frac{2}{3}x+3$

The equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x is $\mathbf{y=-\frac{2}{3}x+3 }$

5 0

3 years ago

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WILL MARK U AS BRAINLIEST!!! Evaluate the following expressions given the functions below:

Scorpion4ik [409]

sorry that was a mistake tee hee

7 0

3 years ago

A textile manufacturer wants to set up a control chart for irregularities (eg. oil stains, shop soil, loose threads, and tears)

Nookie1986 [14]

Answer:

UCLc = 25.7715519

LCLc =-4.171551971

find attached the C-chart(control chart)

Step-by-step explanation:

Sample Irregularities Sample Irregularity Sample Irregularity

1 18 6 11 11 10

2 14 7 4 12 16

3 6 8 10 13 5

4 14 9 12 14 15

5 8 10 9 15 17

Samples/Irre Cont'd

16 - 4

17 - 15

18 - 9

19 - 15

20 - 17

Using these? data, set up a? c-chart with z =33.

UCLc =

LCLc =

Sample irreg mean(CL) UCL LCL

ularities

1 18 10.8 25.77155197 -4.171551971

2 14 10.8 25.77155197 -4.171551971

3 6 10.8 25.77155197 -4.171551971

4 14 10.8 25.77155197 -4.171551971

5 8 10.8 25.77155197 -4.171551971

6 11 10.8 25.77155197 -4.171551971

7 4 10.8 25.77155197 -4.171551971

8 10 10.8 25.77155197 -4.171551971

9 12 10.8 25.77155197 -4.171551971

10 9 10.8 25.77155197 -4.171551971

11 11 10.8 25.77155197 -4.171551971

12 16 10.8 25.77155197 -4.171551971

13 5 10.8 25.77155197 -4.171551971

14 1 10.8 25.77155197 -4.171551971

15 17 10.8 25.77155197 -4.171551971

16 4 10.8 25.77155197 -4.171551971

17 15 10.8 25.77155197 -4.171551971

18 9 10.8 25.77155197 -4.171551971

19 15 10.8 25.77155197 -4.171551971

20 17 10.8 25.77155197 -4.171551971

find attached the C-chart

Download xlsx

5 0

3 years ago

PLZ HELP ASAP TANGENTS OF CIRCLES PROBLEMS

quester [9]

A circumscribed angle is that which is formed by the intersection of the two tangent lines in a circle. With this, we can conclude that segments AC and AB are tangent to circle O. The tangent lines forms a right angle with the radius of the circle drawn from the center of the circle to the tangent point.

By the explanation above, we can say that angles C and B are equal to 90° and that triangle ACO and triangle ABO are congruent. Which means that segment AC is equal to segment AB. Thus, the length of AB is also 4.

<em>Answer: 4 units</em>

7 0

3 years ago

The solution set of IR - 31 = 10 is​

The solution set of IR - 31 = 10 is