Answer:
52
Step-by-step explanation:
We can write this out as an equation. Let's say that the teacher's age is x. Triple the teachers age plus the students age is 163, which can be written out as:

We want to isolate the variable, so subtract 7 from both sides. This gives us:

Finally, we divide both sides by 3, giving:

So the teacher is 52 years old.
Hope this helps!
Answer: 4/9 of the class are boys and 5/9 of the class are girls.
Step-by-step explanation:
- There are 9 nine students in total in the class since 4 + 5 = 9.
- Input the amount of boys and girls there are in the class in the numerator and have 9 as the denominator. 4/9 of the class are boys and 5/9 of the class are girls.
Answer:
It is 13.56
Step-by-step explanation:
You would have to divide 40.68 by 3. 3 goes 1 time into 4 so it is 10.
Answer:
<h2>This is the case % decrease</h2><h2>120000*80/100*90/100</h2><h2>=12*80*90</h2><h2>=7200*12</h2><h2>=72000+ 14400</h2><h2>=86400 rs</h2>
Step-by-step explanation:
Answer:
- 6 bunches of bananas
- 7 pounds of apples
Step-by-step explanation:
We have to assume that a "piece of fruit" is either a bunch of bananas or a pound of apples. Without that assumption, there is insufficient information to work the problem.
Let B represent the number of bunches of bananas. Then 13-B is the number of pounds of apples. The total cost is ...
6B +8(13 -B) = 92
-2B + 104 = 92 . . . . . eliminate parentheses
B = -12/-2 = 6 . . . . . . subtract 104, then divide by the coefficient of B
13-B = 7 . . . . . . . . . . . the number of pounds of apples
The customer bought 6 bunches of bananas and 7 pounds of apples.
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<em>Comment on the solution</em>
You will note that finding the value of the variable involved arithmetic with negative numbers. If you want the numbers to stay positive, then you can choose the variable to represent <em>the most expensive</em> of the items: the number of pounds of apples.