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Arisa [49]
3 years ago
5

5x+8+3x+4=-40+4 plssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss

sssssssssssssss
Mathematics
1 answer:
loris [4]3 years ago
7 0

5

+

8

+

3

+

4

=

−

4

0

+

4

5x+8+3x+4=-40+4

5x+8+3x+4=−40+4

Solve

1

Add the numbers

5

+

8

+

3

+

4

=

−

4

0

+

4

5x+{\color{#c92786}{8}}+3x+{\color{#c92786}{4}}=-40+4

5x+8+3x+4=−40+4

5

+

1

2

+

3

=

−

4

0

+

4

5x+{\color{#c92786}{12}}+3x=-40+4

5x+12+3x=−40+4

2

Combine like terms

3

Add the numbers

4 more steps

Solution

=

−

6

x=-6

x=−6

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Consider the sequence of numbers: 3/8, 3/4, 1 /18, 1 1/2, 1 7/8
vredina [299]

Question:

Consider the sequence of numbers: \frac{3}{8}, \frac{3}{4}, 1\frac{1}{8}, 1\frac{1}{2}, 1\frac{7}{8}

Which statement is a description of the sequence?

(A) The sequence is recursive, where each term is 1/4 greater than its preceding term.

(B) The sequence is recursive and can be represented by the function

f(n + 1) = f(n) + 3/8 .

(C) The sequence is arithmetic, where each pair of terms has a constant difference of 3/4 .

(D) The sequence is arithmetic and can be represented by the function

f(n + 1) = f(n)3/8.

Answer:

Option B:

The sequence is recursive and can be represented by the function

f(n + 1) = f(n) + \frac{3}{8}  .

Explanation:

A sequence of numbers are

\frac{3}{8}, \frac{3}{4}, 1\frac{1}{8}, 1\frac{1}{2}, 1\frac{7}{8}

Let us first change mixed fraction into improper fraction.

\frac{3}{8}, \frac{3}{4}, \frac{9}{8}, \frac{3}{2}, \frac{15}{8}

To find the pattern of the sequence.

To find the common difference between the sequence of numbers.

\frac{3}{4}-\frac{3}{8}=\frac{6}{8}-\frac{3}{8}= \frac{3}{8}

\frac{9}{8}-\frac{3}{4}=\frac{9}{8}-\frac{6}{8}= \frac{3}{8}

\frac{3}{2}-\frac{9}{8}=\frac{12}{8}-\frac{9}{8}= \frac{3}{8}

\frac{15}{8}-\frac{3}{2}=\frac{15}{8}-\frac{12}{8}= \frac{3}{8}

Therefore, the common difference of the sequence is 3.

That means each term is obtained by adding \frac{3}{8} to the previous term.

Hence, the sequence is recursive and can be represented by the function f(n + 1) = f(n) + \frac{3}{8}  .

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you plant 15 tulip bulbs and 10 of them grow into flowers to bloom. If you plant 21 more re tulips bulbs, predict how many of th
harina [27]

Answer:

14 more flower would bloom if 21 more tulip bulb is planted.

Step-by-step explanation:

Given ratio for tulip bulbs and flowers is 15:10.

Now, finding number of flower to bloom if 21 tulip bulb are planted.

Assume if 21 tulip bulbs are planted then number of flower would bloom be"x"

ratio given: \frac{Tulip\ bulbs}{ Flower} = \frac{15}{10} = \frac{21}{x}

Cross multiplying the ratio to get:

⇒x= \frac{21\times 10}{15} = \frac{210}{15}

∴x= 14\ flowers

Hence, 14 flowers would bloom if 21 tulip bulb are planted.

If total tulip bulb is 15+21= 36, then 10+14= 24\ flowers would bloom.

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