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kaheart [24]
2 years ago
14

Can you help me 3(x+2)=2(x+5)

Mathematics
2 answers:
anzhelika [568]2 years ago
7 0

Answer: x = 4

Step-by-step explanation:

3(x+2)=2(x+5)

3x + 6 = 2x + 10

x + 6 = 10

x = 4

podryga [215]2 years ago
7 0
The answer to your question is x=4
You might be interested in
Solve for q.<br> a=qb+r<br> What is q equal to?<br> q=a−r−b<br> q=a−r/b<br> q=a/b −r<br> q=a/rb
Mademuasel [1]

The given equation is a=qb+r

We need to solve the equation for q.

<u>Value of q:</u>

The value of q can be determined by solving the equation a=qb+r for q.

Thus, subtracting both sides of the equation by r, we get;

a-r=qb

Now, dividing both sides of the equation by b, we have;

\frac{a-r}{b}=\frac{qb}{b}

Simplifying the terms, we get;

\frac{a-r}{b}=q

Therefore, the value of q is q=\frac{a-r}{b}

Hence, Option B is the correct answer.

7 0
3 years ago
HELP plz due by 9:00 pm 15 pts. brainliest has to do with ratios.. The polygons are similar. The area of one polygon is given. F
klasskru [66]

Answer:

Step-by-step explanation:

area of smaller triangle=96×(3/12)²=96×1/16=6cm²

8 0
3 years ago
I need help please with step by step it would help me a lot
pav-90 [236]

Answer:

Domain: (-infinity, +infinity) since you can pick any x values.

Range: [0, +infinity) since it does not go below the x axis.

Step-by-step explanation:

The graph is a parabola given by y=x^2

lets pick a few x values:

x = 1 gives us y = 1^2, which = 1

x = -1 gives us y = (-1)^2, which = 1

The parabola's domain is any x value as it extends to infinity.

For its range, you can see that it does not go below the x axis at x = 0. Therefore, the range of the parabola is from [0, infinity]

4 0
3 years ago
at the dog show there are 4 times as many boxers as spaniel if there is a total of 30 dogs. how many dogs are spaniel
alexgriva [62]

4x+x = 30

5x = 30

x = 30/5 =6

 6*4 = 24 boxers

 and 6 spaniels

5 0
3 years ago
How do you find the first five terms of a sequence defined recursively
Blizzard [7]
Interesting question. Good to know for computer science.
Suppose you have a function like 
an = 3x - 2 Try the first couple
a1 = 3(1) - 2
a1 = 3 - 2
a1 = 1

a2 = 3(2) - 2
a2 = 6 - 2
a2 = 4 So each term differs by 3
a2 - a1 = 3

an = a_(n - 1) + 3
a3 = a2 + 3
a3 = 4 + 3 
a3 = 7

a4 = a3 + 3
a4 = 7 + 3
a4 = 10

a5 = a4+ 3
a5 = 10 + 3
a5 = 13

I'll do one more and then check it.
a6 = a5 + 3
a6 = 13 + 3
a6 = 16

a6 = 3x -2
a6 = 3*6 - 2
a6 = 18 - 2
a6 = 16 which checks.

So the general formula is
an = a_(n - 1) * k if you were multiplying or
an = a_(n - 1) + k if you were adding. The key thing is that you are working with the previous term.
6 0
2 years ago
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