V = A*h / 3
A = 5*12 / 2 = 60 / 2 = 30 m²
h = 9 m
________________
V = 30*9 / 3
V = 10*9
V = 90 m³
<span>Given- f(x) = 2x + 5
g(x) = (-1/3)x + 2 , f(1)/g(3) = ?
Solution- f(1) = 2*1 + 5
f(1) = 7
g(3) = (-1/3)*3 + 2
g(3) = -1 + 2
g(3) = 1
So, f(1)/g(3) = 7/1
f(1)/g(3) = 7</span>
1) y=(7/2)x-2.
Slope is the coefficient of x, that is 7/2
Intercept x is the value of x when y = 0 ==> 0=(7/2) X - 2==> 7/2x=2 &x=4/7
so intercept x, (4/7,0)
Intercept y is the value of y when x=0 ==> y= (7/2).(0) - 2 ==> y = 2
and so intercept y, (0,-2)
Now you will follow the same logic to find the are same questions
2) y= -6x + 3 ==>Slope= -6, Intercept x =1/2 & intercept y=3
3) y=-5 has a slope 0 (it doesn't exist). The graph is a line // to x-axis at y=-5
4)y=(6/5)x + 1:==>Slope= -5/6, Intercept x =-5/6 & intercept y=1
5) y=(1/4)x + 2 ==>Slope= 1/4, Intercept x =-8 & intercept y=2
6) x=5, this ligne is // to y axis at x=-5