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3 years ago

Which expression is equivalent to (x^4/3x^2/3)^1/3 brainly

Mathematics

1 answer:

arsen [322]3 years ago

3 0

(x^4/3x^2/3)^1/3

using the power of powers rule (multiply the exponents)

x^(4/3*1/3) x^(2/3* 1/3)

x^ (4/9) ( x^ 2/9)

when multiply exponents, we add

x^ (4/9 + 2/9)

x^ (6/9)

x^ (2/3)

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The actual length of a soccer field is 500 feet find the percent of error

oee [108]

200 yards bozo yeejrkrjrjthbthttjtjtnrm

3 0

3 years ago

The quotient of a number w and(-8), which is then increased by 7

Colt1911 [192]

Okay, since quotient is the answer to a division problem, you will divide w and -8. Increased means to add so, you will +7.

w/-8 +7 is what the expression looks like.

5 0

3 years ago

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

$f(x,y,z) = \left \{ {{Ce^{-(0.5x + 0.2y + 0.1z)}; x,y,z\geq0 } \atop {0}; Otherwise} \right.$

The value of constant C can be obtained as:

$\int_x( {\int_y( {\int_z {f(x,y,z)} \, dz }) \, dy }) \, dx = 1$

$\int\limits^\infty_0 ({\int\limits^\infty_0 ({\int\limits^\infty_0 {Ce^{-(0.5x + 0.2y + 0.1z)} } \, dz }) \, dy } )\, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y }(\int\limits^\infty_0 {e^{-0.1z} } \, dz }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ]) } \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}] } \, dy }) \, dx =1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0 }) \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}] } \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}] } \, dx = 1$

$50C([\frac{-e^{-0.5x} }{0.5}]^\infty__0}) = 1$

$50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1$

$50C[0+\frac{1}{0.5} ] =1$

$100C = 1$ ⇒ $C = \frac{1}{100}$

C = 0.01

3 0

2 years ago

in triunghiul isoscel ABC, AB=AC=36cm, m(BAC)=45°, iar BE perpendicular pe AC, E apartine (AC). Calculati Aria ABC, BE

melisa1 [442]

when given SAS, the area (A) of the triangle = (side1 · sin θ · side2)/2

A = (36 · sin 45° · 36)/2

= (36² · √2)/4

= 9 · 36 · √2

= 324√2

≈ 458.2

4 0

3 years ago

Need It Fast please! =)

Mashcka [7]

Answer:

split the other three in half

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers