You can write three equations in the numbers of nickels (n), dime (d), and quarters (q).
n + d + q = 23 . . . . . . . there are 23 coins total
0n +d -q = 2 . . . . . . . . .there are 2 more dimes than quarters
5n +10d +25q = 250 . .the total value is $2.50
The collection includes 11 nickels, 7 dimes, and 5 quarters.
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I used the matrix function of my calculator to solve these equations. You can find q by subtracting from the last equation five times the sum of the first two equations.
(5n +10d +25q) -5((n +d +q) +(d -q)) = (250) -5(23 +2)
25q = 125 . . . . . . . simplify
q = 5
From the second equation,
d = q +2 = 7
And from the first,
n = 23 -5 -7 = 11
Answer:
3n^2 - 5n - 28
Step-by-step explanation:
(n - 4)(3n + 7)
3n^2 + 7n - 12n - 28
3n^2 - 5n - 28
hope this hepls!!!
The answer is:
v ≈ 1272.35 in^3
Sorry if this does not help.
(1,2)(4,-1)
slope = (y2 - y1) / (x2 - x1)
slope = (-1 - 2) / (4 - 1) = -3/3 = -1
the slope is -1......I am not sure of the mistake.....unless she just added (-1 - 2) and got 3 instead of -3.......or when dividing -3/3....she maybe forgot about the negative sign
Answer:
1,2,3,4,5,6,7,8,9,10,11,12
Step-by-step explanation:
hehhehe easy
