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Lady bird [3.3K]
3 years ago
10

In triangle abc, if A=120 degrees, a=8 and b=3, then angle B=

Mathematics
1 answer:
CaHeK987 [17]3 years ago
6 0

The angle of B is \angle B=19^{\circ}

Explanation:

It is given that \angle A=120^{\circ} and a=8, b=3

To determine the \angle B, let us use the law of sine formula.

Thus, we have,

\frac{Sin A}{a} =\frac{Sin B}{b}

Substituting the values in the formula, we have,

\frac{Sin 120}{8} =\frac{Sin B}{3}

Multiplying both sides by 3,we get,

\frac{3(0.866)}{8} ={Sin B}

Simplifying and dividing, we get,

0.32475=Sin B

Multiplying both sides by \sin ^{-1}, we get,

\sin ^{-1}(0.32475)=B

Thus, B=18.95^{\circ}=19^{\circ}

Hence, The angle of B is \angle B=19^{\circ}

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If a rectangle has an area of x^2+x-20 and a width of x-4, what is the length?
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This synthetic division results in a remainder of 0.  This tells us that 4 (or the corresponding (x - 4) is indeed a root of the polynomial x^2 + x - 20, and so *(x - 4) is a factor.  From the coefficients 1 and 5 we can construct the other factor:  (x - 5).  This (x - 5) represents the length of the rectangle.

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