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3 years ago

Need help solving this math problems

Mathematics

1 answer:

AVprozaik [17]3 years ago

8 0

1) If x is the number of years Naicul works, then the corporate job would earn him

49600x + 2000

dollars, while the teaching job would earn

50000x

dollars. Solve for x such that these two earnings are equal:

49600x + 2000 = 50000x

400x = 2000

x = 5

2) a) At a speed of 6.7 m/s, DJ would finish the race in

(100 m) / (6.7 m/s) ≈ 14.93 s

2) b) If DJ is given a headstart of y seconds, then Usain finishes the race in (9.58 + y) seconds. Solve for y such that this time matches DJ's time from part (a) :

14.93 s = (9.58 + y) s

y ≈ 5.35 s

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Archy [21]

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4 years ago

Read 2 more answers

Please Help !!Mr. Mudd gives each of his children $2000 to invest as part of a friendly family competition. The competition will

VikaD [51]

Answer:

Albert = $2159.07; Marie = $2244.99; Hans = $2188.35; Max = $2147.40

Marie is $10 000 richer

Step-by-step explanation:

Albert

(a) $1000 at 1.2 % compounded monthly

$A = P\left(1 + \dfrac{r}{n}\right)^{nt}$

A = 1000(1 + 0.001)¹²⁰ = $1127.43

(b) $500 losing 2%

0.98 × 500 = $490

(c) $500 compounded continuously at 0.8%

$\begin{array}{rcl}A & = & Pe^{rt}\\& = & 500e^{0.008 \times 10}\\& = &\mathbf{\$541.64}\\\end{array}\\$

(d) Balance

Total = 1127.43 + 490.00+ 541.64 = $2159.07

Marie

(a) 1500 at 1.4 % compounded quarterly

A = 1500(1 + 0.0035)⁴⁰ = $1724.99

(b) $500 gaining 4 %

1.04 × 500 = $520.00

(c) Balance

Total = 1724.99 + 520.00 = $2244.99

Hans

$2000 compounded continuously at 0.9 %

$\begin{array}{rcl}A& = &2000e^{0.009 \times 10}\\& = &\mathbf{\$2188.35}\\\end{array}\\$

Max

(a) $1000 decreasing exponentially at 0.5 % annually

A = 1000(1 - 0.005)¹⁰= $951.11

(b) $1000 at 1.8 % compounded biannually

A = 1000(1 + 0.009)²⁰ = $1196.29

(c) Balance

Total = 951.11 + 1196.29 = $2147.40

Marie is $ 10 000 richer at the end of the competition.

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4 years ago

The work shown is a way to derive Tangent (x + y) = StartFraction tangent (x) + tangent (y) Over 1 minus tangent (x) tangent (y)

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Answer:

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3 years ago

The 2nd, 6th, 8th terms of an A.P. form a G.P. , find the common ratio and the general term of the G.P.

melisa1 [442]

The terms of an arithmetic progression, can form consecutive terms of a geometric progression.

The common ratio is: $\mathbf{r = \frac{a + 5d}{a + d}}$
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