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Sauron [17]
3 years ago
5

Write the equation of the line that passes through the point (-2,4) and has a slope of 4.

Mathematics
1 answer:
NikAS [45]3 years ago
7 0

Answer:

Step-by-step explanation:

alright! let's do it

y =mx + b

the slop would be "m"

y = 4x+b

and then, let's plot -2 to x and 4 to y.

why? well to find " b " as y intercept

4 = 4(-2) +b

4 = -8 +b

4 = -8 +b

+8    +8         both side add 8  to keep the same between 2 sides

12 = b

so:

y = 4x +12

and done! hope you enjoy!

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both numbers in table have one digit and 3 digit what is the relationship between the values represented in these digits ​
maks197457 [2]

Answer:

inverse

Step-by-step explanation:

8 0
2 years ago
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Is 3x + 2y = 6 a function??
professor190 [17]

Answer:

B :)

Step-by-step explanation:

5 0
3 years ago
Write an equation in point slope form for the line with a slope of 3 passes through (1,2)
alexgriva [62]

Answer:

y-2=3(x-1)

Step-by-step explanation:

The point-slope form of a line is given as:

y-y_1=m(x-x_1)

Where

m is the slope

x_1 is the x-coordinate of the point given (passing through the line)

y_1 is the y-coordinate of the point given (passing through the line)

Now,

Given,

Slope = m = 3

x_1 = 1

y_1 = 2

Now, we simply plug these into the formula for point-slope form of a line:

y-y_1=m(x-x_1)\\y-2=3(x-1)

This is the point-slope form.

4 0
3 years ago
In a population of 10,000, there are 5000 nonsmokers, 2500 smokers of one pack or less per day, and 2500 smokers of more than on
Kazeer [188]

Answer:

In one month, we will have 4,950 non-smokers, 2,650 smokers of one pack and 2,400 smokers of more than one pack.

In two months, we will have 4,912 non-smokers, 2,756 smokers of one pack and 2,332 smokers of more than one pack.

In a year, we will have 4,793 non-smokers, 3,005 smokers of one pack and 2,202 smokers of more than one pack.

Step-by-step explanation:

We have to write the transition matrix M for the population.

We have three states (nonsmokers, smokers of one pack and smokers of more than one pack), so we will have a 3x3 transition matrix.

We can write the transition matrix, in which the rows are the actual state and the columns are the future state.

- There is an 8% probability that a nonsmoker will begin smoking a pack or less per day, and a 2% probability that a nonsmoker will begin smoking more than a pack per day. <em>Then, the probability of staying in the same state is 90%.</em>

-  For smokers who smoke a pack or less per day, there is a 10% probability of quitting and a 10% probability of increasing to more than a pack per day. <em>Then, the probability of staying in the same state is 80%.</em>

- For smokers who smoke more than a pack per day, there is an 8% probability of quitting and a 10% probability of dropping to a pack or less per day. <em>Then, the probability of staying in the same state is 82%.</em>

<em />

The transition matrix becomes:

\begin{vmatrix} &NS&P1&PM\\NS&  0.90&0.08&0.02 \\  P1&0.10&0.80 &0.10 \\  PM& 0.08 &0.10&0.82 \end{vmatrix}

The actual state matrix is

\left[\begin{array}{ccc}5,000&2,500&2,500\end{array}\right]

We can calculate the next month state by multupling the actual state matrix and the transition matrix:

\left[\begin{array}{ccc}5000&2500&2500\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] =\left[\begin{array}{ccc}4950&2650&2400\end{array}\right]

In one month, we will have 4,950 non-smokers, 2,650 smokers of one pack and 2,400 smokers of more than one pack.

To calculate the the state for the second month, we us the state of the first of the month and multiply it one time by the transition matrix:

\left[\begin{array}{ccc}4950&2650&2400\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] =\left[\begin{array}{ccc}4912&2756&2332\end{array}\right]

In two months, we will have 4,912 non-smokers, 2,756 smokers of one pack and 2,332 smokers of more than one pack.

If we repeat this multiplication 12 times from the actual state (or 10 times from the two-months state), we will get the state a year from now:

\left( \left[\begin{array}{ccc}5000&2500&2500\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] \right)^{12} =\left[\begin{array}{ccc}4792.63&3005.44&2201.93\end{array}\right]

In a year, we will have 4,793 non-smokers, 3,005 smokers of one pack and 2,202 smokers of more than one pack.

3 0
3 years ago
What Is the solution to the system of equations? Y=-3x-2<br> 5x+2y=15
snow_tiger [21]

Answer:

x,y=-19,55

Step-by-step explanation:

plug in y.

5x+2(-3x-2)=15

5x-6x-4=15

-x=19

x=-19.

Plug in.

y=-3(-19)-2

y=55

correct is B.

Hope this helps :D

3 0
3 years ago
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