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3 years ago

Triangle DABC is similar to DEFG.

Mathematics

2 answers:

lyudmila [28]3 years ago

7 0

Answer:

is there an image provided?

Step-by-step explanation:

stiks02 [169]3 years ago

7 0

The correct answer I believe is c

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Solve by substitution. Please show work -x+9y=-5 x-5y=1

kkurt [141]

Let's solve for x.

−x+9y=−5

Step 1: Add -9y to both sides.

−x+9y+−9y=−5+−9y

−x=−9y−5

Step 2: Divide both sides by -1.

−x ÷ −1 = −9y−5 ÷ −1

x=9y+5

THE ANSWER FOR THE OTHER EQUATION: (x-5y=1)

Let's solve for x.

x−5y=1

Step 1: Add 5y to both sides.

x−5y+5y=1+5y

x=5y+1

Answer:

x=5y+1

I hope this helped I was a little confused on what your problem meant...so if this is not what you asked for just lmk so I can fix it for you :)

3 0

3 years ago

Cathrine has £7000 to invest.

Anvisha [2.4K]

Since this is a compound interest problem, you have to take note that the amount Catherine will get per year is not the same. It will increase per year since it is compounded. So first, we get the amount after one year. This will be 7000 x 0.04 which is 280 plus 7280. In the second year, she will get 7571 (7280 x 0.04 + 7280). In the third year, she will get 7874 (7571 x 0.04 + 7571). In the fourth year, she will get 8189 (7874 x 0.04 + 7874). And finally in the fifth year, she will get 8517 (8189 x 0.04 +8189). So after five years, she has 8517

4 0

3 years ago

What is the value of the expression below? (3 1/2 - 9 3/4) ÷ (-2.5)

Alexandra [31]

Answer:

2.5

Step-by-step explanation:

3 1/2 - 9 3/4 =

3 2/4 - 9 3/4 = -6 1/4

-6 1/4 = -6.25 ÷ (-2.5) = 2.5

5 0

3 years ago

What is the answer to the equation?

Marizza181 [45]

$11 - 2r + 3 = 4 \\ - 2r = 4 - 3 - 11 \\ - 2r = - 10 \\ r = - 10 \div - 2 = 5$

7 0

4 years ago

Read 2 more answers

The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with mean of 1262 and a s

Andrew [12]

Answer:

a) 1186

b) Between 1031 and 1493.

c) 160

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with mean of 1262 and a standard deviation of 118.

This means that $\mu = 1262, \sigma = 118$