The concentration of the diluted solution is 0.0625 M.
<h3>What is concentration?</h3>
The term concentration refers to the amount of substance present in solution.
1) To find the mass of the compound;
mass/134 g/mol = 1.40x10-2M × 100/1000
mass = 1.40x10-2M × 100/1000 × 134 g/mol
mass = 0.19 g
2) To find the molarity of the solution;
2.50 g/40 = 100/1000 × M
M = 2.50 g/40 × 1000/100
M = 0.625 M
3) Using;
C1V1 = C2V2
0.625 M × 10.00mL = C2 × 100.00 mL
C2 = 0.625 M × 10.00mL/ 100.00 mL
C2 = 0.0625 M
Learn more about concentration: brainly.com/question/3045247
Answer:
The answer to your question is limiting reactant = Fe
Explanation:
Data
moles of Fe = 2
moles of O₂ = 6
Process
1.- Write the balanced chemical reaction
Fe + O₂ ⇒ Fe₂O₃
Reactants Elements Products
1 Fe 2
2 O 3
4Fe + 3O₂ ⇒ 2Fe₂O₃
Reactants Elements Products
4 Fe 4
6 O 6
2.- Use the balanced chemical reaction to determine the limiting reactant.
Theoretical proportion of reactants 4 moles Fe / 3 moles O₂ = 1.33
Experimental proportion of reactants = 2 moles Fe/6 moles O₂ = 0.333
3.- Conclusion
As the experimental proportion was lower than the theoretical we conclude that the amount of Fe was lower in the experiment which is the limiting reactant.
Answer:
a
n=m/M
mass if 85 gms and molar mass is 169.87 g/mol
85/169.87=0.50038 moles
Explanation:
Answer:
Yes
Explanation:
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