In which substance does phosphorus have a +3 oxidation state?
1 answer:
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Answer:
The maximum kinetic energy of electron is = 2.93 × Joule
Explanation:
We know that total energy
------------ (1)
Here h = plank's constant = 6.62 × J s
c = speed of light = 3 ×
= 261 nm = 261 ×
m
Put all these values in equation (1) we get
E = 7.6 × J
We know that
Total energy = Energy to remove an electron + K.E of electron
Energy to remove an electron =
Energy to remove an electron = 4.67 × J
K.E of electron = Total energy - Energy to remove an electron
K.E of electron = 7.6 × - 4.67 ×
K.E of electron = 2.93 × Joule
Therefore the maximum kinetic energy of electron is = 2.93 × Joule
There are three possible Isomers for Molecular Formula C₃H₄. Isomers are;
1) Propyne
2) Propa-1,2-diene
3) Cyclopropene
Structures of all three isomers are given below.
There are no geometrical isomers for given molecular formula because geometrical isomers are formed in compounds containing double bond with at least two bulky groups at both sp² hybridized carbons. In given isomers, propyne does not contain any double bond, Propa-1,2-diene is symmetrical in nature while cyclopropene is a 3-membered ring. And for cycloalkenes there must be other groups attached to ring other than Hydrogen atom, hence cyclopropene does not contain any other group, so it can not show geometrical isomerism.
1) Propyne
2) Propa-1,2-diene
3) Cyclopropene
Structures of all three isomers are given below.
There are no geometrical isomers for given molecular formula because geometrical isomers are formed in compounds containing double bond with at least two bulky groups at both sp² hybridized carbons. In given isomers, propyne does not contain any double bond, Propa-1,2-diene is symmetrical in nature while cyclopropene is a 3-membered ring. And for cycloalkenes there must be other groups attached to ring other than Hydrogen atom, hence cyclopropene does not contain any other group, so it can not show geometrical isomerism.