Answer:
(a)

(b)

Explanation:
Hello,
(a) In this case, as the reaction is second-ordered, one uses the following kinetic equation to compute the concentration of NOBr after 22 seconds:
![\frac{1}{[NOBr]}=kt +\frac{1}{[NOBr]_0}\\\frac{1}{[NOBr]}=\frac{0.8}{M*s}*22s+\frac{1}{0.086M}=\frac{29.3}{M}\\](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5BNOBr%5D%7D%3Dkt%20%2B%5Cfrac%7B1%7D%7B%5BNOBr%5D_0%7D%5C%5C%5Cfrac%7B1%7D%7B%5BNOBr%5D%7D%3D%5Cfrac%7B0.8%7D%7BM%2As%7D%2A22s%2B%5Cfrac%7B1%7D%7B0.086M%7D%3D%5Cfrac%7B29.3%7D%7BM%7D%5C%5C)
![[NOBr]=\frac{1}{29.2/M}=0.0342M](https://tex.z-dn.net/?f=%5BNOBr%5D%3D%5Cfrac%7B1%7D%7B29.2%2FM%7D%3D0.0342M)
(b) Now, for a second-order reaction, the half-life is computed as shown below:
![t_{1/2}=\frac{1}{k[NOBr]_0}](https://tex.z-dn.net/?f=t_%7B1%2F2%7D%3D%5Cfrac%7B1%7D%7Bk%5BNOBr%5D_0%7D)
Therefore, for the given initial concentrations one obtains:

Best regards.
Answer:
Standard pressure is always 1.00atm. Example #1: How many moles of oxygen will occupy a volume of 2.50 L at STP? Standard temperature = 273K law.
Explanation:
Answer:
These substances are called amphiprotic. Water, amino acids, hydrogen carbonate ions, and hydrogen sulfate ions are common examples.
Explanation:
A substance is amphoteric (from Greek amphoteros = "each of two") if it can act as an acid or a base.
For example, aluminum hydroxide is amphoteric because it can act as a base and neutralize strong acids.
Avogadro's law states that in one mole of a substance, there are
molecules.
This means that in 1.55 moles, there are 
Answer:
<h2>The answer is 0.95 L</h2>
Explanation:
In order to find the volume when the pressure is changed to 5.30 atm we use Boyle's law which is

where
P1 is the initial pressure
P2 is the final pressure
V1 is the initial volume
V2 is the final volume
Since we are finding the final volume

From the question
P1 = 2.82 atm
V1 = 1.79 L
P2 = 5.30 atm
So we have

We have the final answer as
<h3>0.95 L</h3>
Hope this helps you