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Rama09 [41]
3 years ago
13

How do you solve this problem?

Mathematics
1 answer:
zzz [600]3 years ago
4 0
1/8x=3
x=3×8
x=24
There are 24 students in Ted's class.

Hope my answer helped u :)
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Consider the parabola y = 8x − x2. (a) find the slope of the tangent line to the parabola at the point (1, 7). 6 (b) find an equ
Brut [27]
In order to find any of the info we need we have to find the first derivative of the equation.  If y=-x^2+8x,  then  y'=-2x+8.  We are told to find the slope at point (1, 7).  Using that x value in our derivative will give us the slope of the line at that point.  y' = -(1)^2+8.  So y' = 7.  That's the slope of the line.  Now we will use that slope along with the x and y coordinate in the slope-intercept form of a line to solve for b.  7 = 7(1) + b so b = 0.  Our equation then is y = 7x.  If you graph these in the same window on your calculator, you can see how perfectly that align at the given point.  It's really quite perfect.
5 0
3 years ago
Read 2 more answers
PLZ HELP FAST multiple choice<br>touching spirit bear​
Juli2301 [7.4K]
Look this up
On quizlet it will give you the answer
5 0
3 years ago
Solve for e 9e^f=49<br> PLEASE HELP ASAP!!!
Kamila [148]

B is the correct answer

5 0
3 years ago
PLEASE HELP <br>I need the answers for all of the ones that I haven't done please. Thank you!
Rudik [331]
#2.

a) 1/4m + 3 = 2

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m = -4

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4y - 3y + 24 = 12

y = -12



For #10, letter b. Do the same thing you did with letter a.
The equation is already given.
You have your y-intercept: -8, and your slope: 3/1.

These two create two different points you can add to your data table.

(0, -8) and (1, 3)

y:-8, 3
x: 0, 1

6 0
4 years ago
Can someone please help me
zalisa [80]
It is the first one because fist you reflect it to the right across the y axis, then you reflect it down across the x axis, and last but not least, you reflect it left across the y axis where it is now

hope this is helpful! :)
4 0
3 years ago
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