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denis-greek [22]
2 years ago
11

If gh-f=g-h, which of the following gives g in terms of the other variables?

Mathematics
1 answer:
JulsSmile [24]2 years ago
5 0

The value of g in terms of other variables is g=\frac{f+h}{h-1}

Given the expression;

gh-f=g-h

We are to express g in terms of other variables as shown;

gh-f=g-h

Collect the like terms

gh - g = f + h

Factor out g

g(h - 1) = f + h

Divide both sides by h-1

g=\frac{f+h}{h-1}

Hence the value of g in terms of other variables is g=\frac{f+h}{h-1}

Learn more here: brainly.com/question/21406377

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determine the point of intersection of the following pair of lines ............2x-3y-4=-13 and 5x=-2y+25. 3x+2y-7=0 and 2x=12-5y
grandymaker [24]

Answer:

  1. (x, y) = (3, 5)
  2. (x, y) = (1, 2)

Step-by-step explanation:

A nice graphing calculator app makes these trivially simple. (See the first two attachments.) It is available for phones, tablets, and as a web page.

__

The usual methods of solving a system of equations involve <em>elimination</em> or <em>substitution</em>.

There is another method that is relatively easy to use. It is a variation of "Cramer's Rule" and is fully equivalent to <em>elimination</em>. It makes use of a formula applied to the equation coefficients. The pattern of coefficients in the formula, and the formula itself are shown in the third attachment. I like this when the coefficient numbers are "too messy" for elimination or substitution to be used easily. It makes use of the equations in standard form.

_____

1. In standard form, your equations are ...

  • 2x -3y = -9
  • 5x +2y = 25

Then the solution is ...

  x=\dfrac{-3(25)-(2)(-9)}{-3(5)-(2)(2)}=\dfrac{-57}{-19}=3\\\\y=\dfrac{-9(5)-(25)(2)}{-19}=\dfrac{-95}{-19}=5\\\\(x,y)=(3,5)

__

2. In standard form, your equations are ...

  • 3x +2y = 7
  • 2x +5y = 12

Then the solution is ...

  x=\dfrac{2(12)-5(7)}{2(2)-5(3)}=\dfrac{-11}{-11}=1\\\\y=\dfrac{7(2)-12(3)}{-11}=\dfrac{-22}{-11}=2\\\\(x,y)=(1,2)

_____

<em>Note on Cramer's Rule</em>

The equation you will see for Cramer's Rule applied to a system of 2 equations in 2 unknowns will have the terms in numerator and denominator swapped: ec-bf, for example, instead of bf-ec. This effectively multiplies both numerator and denominator by -1, so has no effect on the result.

The reason for writing the formula in the fashion shown here is that it makes the pattern of multiplications and subtractions easier to remember. Often, you can do the math in your head. This is the method taught by "Vedic maths" and/or "Singapore math." Those teaching methods tend to place more emphasis on mental arithmetic than we do in the US.

7 0
3 years ago
Yolanda left for a youth retreat at 8:00 p.m. On Friday. She came home on Sunday morning at 10:00 a.m. How long was Yolanda away
weeeeeb [17]
Yolanda was gone for 12 hours 
6 0
3 years ago
Read 2 more answers
A green number cube and a red number cube are rolled. An outcome is the pair of numbers rolled on the two different cubes. Which
Ber [7]

Answer:

None of the above

Step-by-step explanation:

The common ratio 10 means we are starting with 4.5 and multiplying that by 10 each time:

4.5*10=45

45*10=450

450*10=4500

As you can see, this does not match any of the answers

Read more on Brainly.com - brainly.com/question/14993026#readmore

4 0
3 years ago
Plz help fast
xz_007 [3.2K]

Answer:

the function y=5x+5

plug in the hours 4.5 for x

y=5(4.5)+5

=27.5kilometers

3 0
2 years ago
In a random sample of 8 people, the mean commute time to work was 36.5 minutes and the standard deviation was 7.4 minutes. A 98%
ANEK [815]

Answer:

Step-by-step explanation:

Given that

Sample size = n = 8: sample mean = 36.5 and s = sample std dev = 7.4 minutes

98% CI using t = (28.7, 44.3) with margin of error as 7.8

Now if sigma = population std dev is known we use Z critical value

Margin of error = 2.33*8.7/\sqrt 8 = 7.167

CI = (36.5 ±7.167)

This is not wider than that used using t distribution

The margin of error of u is ___7.167

98% confidence interval using the standard normal distribution is (29.333__,43.667__)

d)the confidence interval found using the standard normal distrubution is narrower than the confidence interval found using the students t-distribution

3 0
3 years ago
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