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wlad13 [49]
3 years ago
6

What is the answer please help

Mathematics
1 answer:
maria [59]3 years ago
8 0

Answer:

25

Step-by-step explanation:

x^2=24^2+7^2

    =576+49

   =625

x=25

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Please help with all 3 questions.
mixas84 [53]

Answer:

1. *2/multiplied by 2, since each number gets higher by *2.

2. *3/multiplied by 3, since each number gets higher by *3

3. ÷2/divided by 2, since each number gets lower by ÷2.

5 0
2 years ago
here are 5 classes in your grade level. Each class is 6/7 full today. If a full class has 28 students, how many students in your
Crazy boy [7]

Answer:

A minimum of 24 students if all the students share a class with you. Not enough info to decide the largest size of grade.

Step-by-step explanation:

6 0
3 years ago
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A swimmer swam 48 kilometers in d days. What is the value of d if the averge amount swan was 3.2 kilometers?
AnnZ [28]

To find the number of days, divide the total swam by the average:

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They swam for 15 days.

3 0
3 years ago
Which number line shows point A at 3, point B at −1.5, point C at , and point D, which is the opposite of point A?
Oduvanchick [21]

Step-by-step explanation:

We have that point A is at 3.

This is 3 units to the right of 0 on the number line.

The point that is opposite of A should be 3 units to the left of 0.

That point will be at -3.

Therefore you have to choose the point that is on -3.

It should be similar to one in the attachment.

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=prove%20that%5C%20%20%5Ctextless%20%5C%20br%20%2F%5C%20%20%5Ctextgreater%20%5C%20%5Cfrac%20%7B
inysia [295]

\large \bigstar \frak{ } \large\underline{\sf{Solution-}}

Consider, LHS

\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}

We know,

\begin{gathered}\boxed{\sf{  \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered}  \\  \\  \text{So, using this identity, we get} \\  \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}

We know,

\begin{gathered}\boxed{\sf{  \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered}  \\

So, using this identity, we get

\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}

can be rewritten as

\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}

<h2>Hence,</h2>

\begin{gathered} \\ \rm\implies \:\boxed{\sf{  \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}

\rule{190pt}{2pt}

5 0
2 years ago
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