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dangina [55]
3 years ago
11

I need numbers 1,2,3,6,8,10, and 25

Mathematics
1 answer:
Aliun [14]3 years ago
4 0

Answer:

What subject is this?. May you please take apicture clear so i can see perfectly

thank you by Tracy Stewart

Step-by-step explanation:

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Solving quadratic formulas<br> 8y²-30y+27=2
Bess [88]
Y=5/2, 5/4 your welcome
6 0
2 years ago
HELP! What is the measure of angle ABE? WILL GIVE BRAINLIEST!
Mazyrski [523]

Answer:

Step-by-step explanation:

Bisection is the division of a line or an angle into two equal halves. It means that a bisector is a line that divides an angle or another line into two equal halves. Therefore,

Line BE divides angle ABC into two equal halves. This means that

Angle ABC/2 = angle ABE = angle EBC

Therefore,.

2x + 20 = 4x - 6

4x - 2x = 20 + 6

2x = 26

x = 26/2 = 13

Therefore,

Angle ABE = 2 × 13 + 20

= 46 degrees

8 0
3 years ago
Find the number of terms and the degree of this polynomial. -9
Korvikt [17]

Answers:

  • Number of terms: 1
  • Degree:  9

===============================================

Explanation:

This is consider a monomial since we only have one term. Terms are separated by a plus sign, so something like 5x^2+10x has two terms.

The degree of a polynomial is the largest exponent when dealing with single variables. In the case of 9r^9, the largest exponent is 9, so the degree is 9. Going back to an example like 5x^2+10x, the largest exponent is 2 so this is the degree of this example.

8 0
3 years ago
Solution for: <br> -x + 3y -2z = 19<br> 2x + y - z = 5<br> -3x - y + 2z = -7
STatiana [176]

Answer:

x = -1 , y = 4 , z = -3

Step-by-step explanation:

Solve the following system:

{-x + 3 y - 2 z = 19 | (equation 1)

2 x + y - z = 5 | (equation 2)

-3 x - y + 2 z = -7 | (equation 3)

Swap equation 1 with equation 3:

{-(3 x) - y + 2 z = -7 | (equation 1)

2 x + y - z = 5 | (equation 2)

-x + 3 y - 2 z = 19 | (equation 3)

Add 2/3 × (equation 1) to equation 2:

{-(3 x) - y + 2 z = -7 | (equation 1)

0 x+y/3 + z/3 = 1/3 | (equation 2)

-x + 3 y - 2 z = 19 | (equation 3)

Multiply equation 2 by 3:

{-(3 x) - y + 2 z = -7 | (equation 1)

0 x+y + z = 1 | (equation 2)

-x + 3 y - 2 z = 19 | (equation 3)

Subtract 1/3 × (equation 1) from equation 3:

{-(3 x) - y + 2 z = -7 | (equation 1)

0 x+y + z = 1 | (equation 2)

0 x+(10 y)/3 - (8 z)/3 = 64/3 | (equation 3)

Multiply equation 3 by 3/2:

{-(3 x) - y + 2 z = -7 | (equation 1)

0 x+y + z = 1 | (equation 2)

0 x+5 y - 4 z = 32 | (equation 3)

Swap equation 2 with equation 3:

{-(3 x) - y + 2 z = -7 | (equation 1)

0 x+5 y - 4 z = 32 | (equation 2)

0 x+y + z = 1 | (equation 3)

Subtract 1/5 × (equation 2) from equation 3:

{-(3 x) - y + 2 z = -7 | (equation 1)

0 x+5 y - 4 z = 32 | (equation 2)

0 x+0 y+(9 z)/5 = (-27)/5 | (equation 3)

Multiply equation 3 by 5/9:

{-(3 x) - y + 2 z = -7 | (equation 1)

0 x+5 y - 4 z = 32 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Add 4 × (equation 3) to equation 2:

{-(3 x) - y + 2 z = -7 | (equation 1)

0 x+5 y+0 z = 20 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Divide equation 2 by 5:

{-(3 x) - y + 2 z = -7 | (equation 1)

0 x+y+0 z = 4 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Add equation 2 to equation 1:

{-(3 x) + 0 y+2 z = -3 | (equation 1)

0 x+y+0 z = 4 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Subtract 2 × (equation 3) from equation 1:

{-(3 x)+0 y+0 z = 3 | (equation 1)

0 x+y+0 z = 4 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Divide equation 1 by -3:

{x+0 y+0 z = -1 | (equation 1)

0 x+y+0 z = 4 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Collect results:

Answer:  {x = -1 , y = 4 , z = -3

6 0
3 years ago
Write out .540 in words
Len [333]

Answer:

Five hundred forty thousandths

3 0
3 years ago
Read 2 more answers
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