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3 years ago

Pls help me with this

Mathematics

1 answer:

Dafna1 [17]3 years ago

6 0

Answer:

50, 10, (70 20 80 60 52 54 90 4 32 44 75 62 46 10 22 70 12 28 55 8 34 32 62 30 38 34 50 105

Step-by-step explanation:

The answer is that it is symettrical

6a. 6105

6b. 1560

7. I dont know this one im so sorry

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If f(x) = 3^+ 10 and g(x) = 2x - 4, find (f - g)(x).

just olya [345]

Answer:

3^x -2x +14

Step-by-step explanation:

I will assume you mean 3^x in the function f(x)

f(x) = 3^x+ 10

g(x) = 2x - 4

(f - g)(x) = 3^x+ 10 - (2x - 4)

Distribute the minus sign

= 3^x+ 10 - 2x + 4

= 3^x -2x +14

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3 years ago

Triangles FEG and FDH are similar. If segment DH is 28 units, what is the measure of segment EG?

postnew [5]

Answer:

28 units

Step-by-step explanation:

Because of triangles FEG and FDH are similar, so DH=EG. Or you can't find out the answer. ;)

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3 years ago

spent $31.50 on centerpieces for 8 tables. she bought candles and vases. candles cost $3 and vases cost $4.25. how much of each

Anettt [7]

Answer:2 candles and 6 vases

Step-by-step explanation:

8 0

3 years ago

5, 3.1.24<br><br> f(x) = 3x² + 5; find f(x + 3) - [f(x) + 3]

Aleks [24]

Given that $f(x) = 3x^2 + 5$ , we have

$f(x + 3) = 3 (x + 3)^2 + 5 \\\\= 3 (x^2 + 6x + 9) + 5 \\\\= 3x^2 + 18x + 32$

so that

$f(x+3) - (f(x) + 3) = (3x^2 + 18x + 32) - (3x^2 + 8) \\\\= \boxed{18x + 24}$

3 0

2 years ago

You are interested in estimating the the mean age of the citizens living in your community. In order to do this, you plan on con

AlladinOne [14]

Using the z-distribution, a sample size of 180 is needed for the estimate.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

$\overline{x} \pm z\frac{\sigma}{\sqrt{n}}$

The margin of error is given by:

$M = z\frac{\sigma}{\sqrt{n}}$

In which:

$\overline{x}$ is the sample mean.

z is the critical value.

n is the sample size.

$\sigma$ is the standard deviation for the population.

In this problem, we have a 98% confidence level, hence $\alpha = 0.98$ , z is the value of Z that has a p-value of $\frac{1+0.98}{2} = 0.99$ , so the critical value is z = 2.327.

The population standard deviation is of $\sigma = 23$ , and to find the sample size, we have to solve for n when M = 4.

Hence:

$M = z\frac{\sigma}{\sqrt{n}}$

$4 = 2.327\frac{23}{\sqrt{n}}$

$4\sqrt{n} = 2.327 \times 23$

$\sqrt{n} = \frac{2.327 \times 23}{4}$

$(\sqrt{n}) = \left(\frac{2.327 \times 23}{4}\right)^2$

n = 179.03.

Rounding up, as a sample size of 179 would result in an error slightly above 4, a sample of 180 is needed.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

8 0

2 years ago

Pls help me with this​

Pls help me with this