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3 years ago

7

Angelica writes a function f with a domain of all real numbers and a range of {-13}. Which of the following could be the functio

n she wrote

1 answer:

leonid [27]3 years ago

4 0

Answer:

Step-by-step explanation:

I just took the test, the correct answer is .. 31.5 in.

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Yoshi is painting a large wall in the park. He measures the wall and finds that the dimensions are 4 m by 20 m. Yoshi has a can

-BARSIC- [3]

No. The area of a square/rectangle is length * height, and 4 * 20 is 80m^2. Because Yoshi has a can of paint that can cover 81m^2, and 81m^2 > 80m^2, Yoshi does NOT need to buy more paint.

8 0

3 years ago

Which model shows two equal expressions when c= 4?

lapo4ka [179]

Answer:

the third answer

Step-by-step explanation:

c = 4

c + 1 = 1 + 1 + 1 + 1 + 1

4 + 1 = 1 + 1 + 1 + 1 + 1

5 = 5

3 0

2 years ago

Use the model to write the equation that represents the problem.

sdas [7]

5/2 • 4/1 (flip the second fraction to multiply)
20/2
10

A

4 0

2 years ago

HELP ME ASAP I NEED HELP PLEASE SOMEONE

scZoUnD [109]

Answer:

welll there no like answers to give here so i dont know might want to check what you post before you post it

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the ex

noname [10]

$L(x,y,z,\lambda)=10x+10y+2z+\lambda(5x^2+5y^2+2z^2-42)$

$L_x=10+10\lambda x=0\implies1+\lambda x=0$

$L_y=10+10\lambda y=0\implies1+\lambda y=0$

$L_z=2+4\lambda z=0\implies1+2\lambda z=0$

$L_\lambda=5x^2+5y^2+2z^2-42=0$

$\begin{cases}L_x=0\\L_y=0\\L_z=0\end{cases}\implies1+\lambda x=1+\lambda y=1+2\lambda z=0\implies x=y=2z$

$5x^2+5y^2+2z^2=5(2z)^2+5(2z)^2+2z^2=42z^2=42\implies z^2=1$

$z^2=1\implies z=\pm1\implies x=y=\pm2$

There are two critical points, at which we have

$f\left(2,2,1\right)=42\text{ (a maximum value)}$

$f\left(-2,-2,-1\right)=-42\text{ (a minimum value)}$

3 0

3 years ago