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Charra [1.4K]
3 years ago
8

PLS HELP ME WITH THIS!!!!!! HOW DID THEY GET 80ft^2

Mathematics
1 answer:
noname [10]3 years ago
7 0

\huge \boxed{\mathfrak{Question} \downarrow}

  • Determine the surface area of the right square pyramid.

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

The formula for finding the surface area of a right square pyramid is ⇨ b² + 2bl, where

  • b = base of the right square pyramid
  • l = slant height of the right square pyramid.

In the given figure,

  • base (b) = 4 ft.
  • slant height (l) = 8 ft.

Now, let's substitute the values of b & l in the formula & solve it :-

\sf \: {b}^{2}  + 2bl \\  =   \sf \: {4}^{2}  + 2 \times 4 \times 8 \\  =  \sf \: 16 + 8 \times 8 \\  =  \sf \: 16 + 64 \\  =  \huge\boxed{\boxed{ \bf 80 \: ft ^{2} }}

So, the surface area of the right square pyramid is <u>8</u><u>0</u><u> </u><u>ft²</u><u>.</u>

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