A rocket is shot in the air at an initial velocity of 12,800 miles per hour. If 1 mile is equal to 5,280 feet, then what is the rocket’s speed, in feet per second, during take-off?
1 answer:
Answer:
67,584,000
Step-by-step explanation:
Since one mile is 5,280 feet you then you will take the amount of miles it is going witch is 12,800 then you multiply them. You get the answer 67,584,000
You might be interested in
Answer:
Equation: x + 5 ≤ 26
Solved: x ≤ 21
V = 4/3πr³
Answer:
0. 33 por que los jamones sivieron a 15 pesos y mi mama se va asta otro lado para compralo
Answer:
-4
Step-by-step explanation:
5+(-3)-6
2-6
-4
Y = 10x
