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Ahat [919]
2 years ago
15

I need helppppppppppp

Mathematics
1 answer:
DiKsa [7]2 years ago
8 0

Answer:

B

Step-by-step explanation:

Moving it to the right one unit and down one unit, you would have the answer be (x + 1, y-1) because moving it to the right is moving it in the direction of the positive numbers and moving it down is moving it in the direction of the negative numbers.

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Write parametric equations of the line through the points (7,1,-5) and (3,4,-2). please use the first point as your base-point w
Roman55 [17]

Given:

A line through the points (7,1,-5) and (3,4,-2).

To find:

The parametric equations of the line.

Solution:

Direction vector for the points (7,1,-5) and (3,4,-2) is

\vec {v}=\left

\vec {v}=\left

\vec {v}=\left

Now, the perimetric equations for initial point (x_0,y_0,z_0) with direction vector \vec{v}=\left, are

x=x_0+at

y=y_0+bt

z=z_0+ct

The initial point is (7,1,-5) and direction vector is \vec {v}=\left. So the perimetric equations are

x=(7)+(-4)t

x=7-4t

Similarly,

y=1+3t

z=-5+3t

Therefore, the required perimetric equations are x=7-4t, y=1+3t and z=-5+3t.

5 0
3 years ago
In an algebra class last year, students who earned grades of A spent 4.7 hours more on homework per week than students who earne
Neko [114]
  <span>A = 4.7 + C 
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3 years ago
Simplify. (-7y^2+4y+9)+(6y^2-5y+9)-(2y^2-9y-2)
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Combine like terms

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hope this helps

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