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artcher [175]
3 years ago
10

The Ragnier's purchased a house for $357,000. They sold their home for $475,000. What was the percent increase?

Mathematics
1 answer:
ehidna [41]3 years ago
7 0

Answer:A

Step-by-step explanation:trust me brother

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Yolanda spends 82/3 hours per month playing soccer. Approximately how many hours does she play soccer in a year?
Vesnalui [34]
328 because 82/3 multiplied by 12 is 328 and you do that because there's 12 months in a year and if you spend 82/3 hours per month playing soccer than you would multiply that by 12 which gives you 328 hours.
7 0
3 years ago
A Survey of 85 company employees shows that the mean length of the Christmas vacation was 4.5 days, with a standard deviation of
GenaCL600 [577]

Answer:

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

Step-by-step explanation:

We have the standard deviations for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 85 - 1 = 84

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 84 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 1.989.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.989\frac{1.2}{\sqrt{85}} = 0.26

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.26 = 4.24 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.26 = 4.76 days

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

92% confidence interval:

Following the sample logic, the critical value is 1.772. So

M = T\frac{s}{\sqrt{n}} = 1.772\frac{1.2}{\sqrt{85}} = 0.23

The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.23 = 4.27 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.23 = 4.73 days

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

8 0
3 years ago
Using what you have learned about solving systems of equations, find the number that represents the apple, banana, and cherry.
erica [24]

it would be convenient if you actually give us the equation

8 0
3 years ago
What is the inverse of y=2x+7
Katyanochek1 [597]
Y=(0,7)
Root: (-7/2,0)
3 0
3 years ago
The value of a car is $20,000. It loses 10.7% of its value every year . Find the approximate monthly decrease in value . Round y
jenyasd209 [6]

Answer:

$178.3

Step-by-step explanation:

The value of a car is $20,000

The car loses 10.7% of its value yearly

Since there are 12 months in a year then 10.7% can be represented as

10.7%/12

= 0.8916%

Therefore the approximate monthly decrease in value can be calculated as follows

= $20,000×0.8916/100

= $20,000×0.008916

= $178.3

Hence the approximate monthly decrease in value is $178.3

7 0
3 years ago
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