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3 years ago

Jason used the commutative property to write an expression that is equivalent to 3

Mathematics

2 answers:

White raven [17]3 years ago

6 0

Answer:Jason is not correct as Jason changed the terms.

Step-by-step explanation:

Given the expression 34+5.6b+9.Jason used the commutative property to write the above expression changed to 9.0 + 56b + 3.4

We have to tell Jason work is correct or not.

Commutative property states that order does not matters but the terms remains same i.e a+b=b+aJason change the expression 34+5.6b+9 to 9.0 + 56b + 3.4here, Jason change the terms as well as order Jason is not correct as Jason changed the terms.

Elanso [62]3 years ago

3 0

Answer: 0.22

Step-by-step explanation:

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What's the value of x in 6(x+3)=24

ra1l [238]

Answer:

X=1

Step-by-step explanation:

6 times x = 6x

6 times positive 3 = 18

6x +18 = 24

-18 -18

6x = 6

6 6

x = 1 :)

4 0

4 years ago

Read 2 more answers

Directions : Factor each of the following Differences of two squares and write your answer together with solution

N76 [4]

$\huge \boxed{\mathfrak{Question} \downarrow}$

Factor each of the following differences of two squares and write your answer together with solution.

$\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}$

$\sf \: x ^ { 2 } - 36$

Rewrite $\sf\:x^{2}-36 as x^{2}-6^{2}$ . The difference of squares can be factored using the rule: $\sf\: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right)$ .

$\boxed{ \boxed{ \bf\left(x-6\right)\left(x+6\right) }}$

__________________

$\sf \: 49 - x ^ { 2 }$

Rewrite 49-x² as 7²-x². The difference of squares can be factored using the rule: $\sf\:a^{2}-b^{2}=\left(a-b\right)\left(a+b\right)$ .

$\sf \: \left(7-x\right)\left(7+x\right)$

Reorder the terms.

$\boxed{ \boxed{ \bf\left(-x+7\right)\left(x+7\right) }}$

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$\sf \: 81 - c ^ { 2 }$

Rewrite 81-c²as 9²-c². The difference of squares can be factored using the rule: $\sf\:a^{2}-b^{2}=\left(a-b\right)\left(a+b\right)$ .

$\sf\left(9-c\right)\left(9+c\right)$

Reorder the terms.

$\boxed{ \boxed{ \bf\left(-c+9\right)\left(c+9\right) }}$

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$\sf \: m ^ { 2 } n ^ { 2 } - 1$

Rewrite m²n² - 1 as $\sf\left(mn\right)^{2}-1^{2}$ . The difference of squares can be factored using the rule: $\sf\:a^{2}-b^{2}=\left(a-b\right)\left(a+b\right)$ .