One of the measurements of dispersion is the standard deviation, which is exclusively used for quantitative data. It aids in determining if the data's mean is a suitable measurement to reflect the core value.

TIME FREQUENCY(f) MIDPOINT(x) d d² fd fd²

0 - 0.9 43 0.45 -3 9 -129 387

1.0 - 1.9 17 1.45 -2 4 -34 68

2.0 - 2.9 19 2.45 -1 1 -19 19

3.0 - 3.9 18 3.45 0 0 0 0

4.0 - 4.9 14 4.45 1 1 14 14

5.0 -5.9 16 5.45 2 4 32 64

∑f = 127

∑fd = -136

∑fd² = 552

$d = \frac{x - 3.45}{1}$

Standard Deviation = $\sqrt \frac{fd^{2} }{N} - \sqrt \frac{(fd)^{2} }{N} * i$

$\sqrt \frac{552}{127} -\sqrt (\frac{-136}{127})^{2} * 1$

√4.35 - √1.15

Standard Deviation = 3.2

(SD)² = (3.2)² = 10.24

Variance = 10.24

To know more about standard deviation, refer to this link :

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7 0

1 year ago

Eric and Frank want to equally share 4/3 feet of rope. what length of rope should each friend get? explain how to use a drawing

blondinia [14]

The rope is 1 and 1/3 long,1 is the same as saying 3/3,
this means that the rope is 3/3 + 1/3 long,so it is 4/3 foot long,
you now want to get half of this number so that each person has an equal length of rope,so multiply the length of rope by a half,
4/3 x 1/2 = 4/6 , which if simplified = 2/3, this means that each friend gets 2/3 foot of rope.

You can draw this in a diagram by drawing the 1 foot of rope, and then dividing it up into 3 sections. Then add the 1/3 foot of rope into the drawing. It should then be easy to see that altogether there are 4 separate sections of rope and that if each friend has two sections then they will be sharing equal amounts, so consequently each friend has two of the thirds of rope, 2/3

4 0

3 years ago