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shusha [124]
3 years ago
15

Now suppose that the 5 (identical) prizes will be distributed among the 8 people. a winner can receive more than one prize. in h

ow many ways could the 5 prizes be distributed?
Mathematics
1 answer:
sweet [91]3 years ago
5 0
The answer to this question would be 792If A is the number of prizes and B is the number of people, the formula that needed to solve this question would be C(A+B-1, B-1) 
If you put the number it will become C(5+8-1, 8-1)= C(12,7)
Then the possible way should be:
12!/ 7! 5!= <span>479001600/ 120*5040= 792 ways</span>
You might be interested in
Fred bought 7 new baseball trading cards to add to his collection. The next
rodikova [14]
His dog ate 1/2 of his collection, this means that there are only 33 left. If I multiply 33x2, I will get 66. Therefore, Fred started with 66 cards.

(If you’re not counting the cards he purchased, then Fred would have 59 cards.)
4 0
3 years ago
A polynomial f (x) has the given zeros of 6, –1, and –3.
butalik [34]

Using the factor theorem the given zeros can be written in the form

f(x) = (x-6)(x+1)(x+3)   where (x-6)=0 ;(x+1)=0; (x+3) =0  

or

f(x) =  (x-6) (x²+4x+3)

f(x) =  x³-6x² +4x²-24x+3x-18

f(x) =  x³-2x²-21x-18

g(x)= \frac{(x-6)(x+3) }{(x-2)}

The equation of the slant asymptote is y= x-1

The polynomial g(x)= x²-3x-18/x-2 has infinite discontinuity at x=2

And x ∈ R: x≠ 2   where R= set of real numbers

Part B:

f (x)= (x² – x – 2)

can be written as

f (x) = (x² – 2x+x – 2)

or

f (x) = (x+1) ( x – 2)

Dividing the original polynomial with the second polynomial to get g(x)

g(x)= \frac{(x-6)(x+1)(x+3) }{(x+1)(x-2)}

g(x)= \frac{(x-6)(x+3) }{(x-2)}

g(x)= x²-3x-18/x-2

The slant asymptote is obtained by dividing the numerator by the denominator

       <u>  x -1          </u>          

x-2√ x²-3x-18

        x² -2x

       <u> -    +    </u>

               -x-18

               -x+2

            <u>    +  -   </u>

                   -20

The equation of the slant asymptote is y= x-1

The polynomial g(x)= x²-3x-18/x-2 has infinite discontinuity at x=2

When  the denominator becomes zero (2-2) then it cannot be defined therefore it is discontinuous.

And x ∈ R: x≠ 2   where R= set of real numbers

The graph shows that it is infinitely discontinuous at point 2

brainly.com/question/4986994

brainly.com/question/9837678

6 0
3 years ago
The perimeter of rectangle is 48ft the length is 16 from. Whats is the area?
solniwko [45]

Answer:

128

Step-by-step explanation:

There are 2 lengths, 16 x 2 = 32. 48 - 32 = 16. 16 divded by 2 equals 8. 8 x 16 = 128.

7 0
3 years ago
What is 1/7 x 140 ( Multiplying fractions by whole numbers using tape diagrams)
satela [25.4K]

Answer:

20

Step-by-step explanation:

20 is your answer

8 0
3 years ago
Roots of x^2+8x+9 by finding in quadratic formula
gladu [14]
The quadratic formula is -b + or - the square root of b squared - 4 times the a value and c value over 2a. So the roots would be -1.354249 and -6.645751. I believe these are the roots. 
4 0
4 years ago
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