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3 years ago

Y=x-2 and x+y=4 by substitution methood

Mathematics

1 answer:

Sav [38]3 years ago

5 0

Answer:

first of all,

y=x-2 (equation 1)

x+y=4 (equation 2)

put y= x-2 into x+y=4

Then,

x+(x-2) =4

x+x-2= 4

2x-2=4

2x= 4+2

2x= 6

divide both sides by the coefficient of x,

x=3

Then,

put x=3 in equation 1

y= 3-2

y=1

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(6 + root27)/(4 - root3) can be written in the form (r + sroot3)/13

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Step-by-step explanation:

Rationalise the denominator by multiplying both numerator and denominator by the conjugate of the denominator.

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Y=x-2 and x+y=4 by substitution methood​

Y=x-2 and x+y=4 by substitution methood