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Lesechka [4]
2 years ago
14

(PLS HURRY I'LL MARK BRAINLIEST)

Mathematics
1 answer:
ch4aika [34]2 years ago
8 0

Answer:

<u>Answer</u><u>:</u><u> </u><u>(</u><u>0</u><u>,</u><u> </u><u>-</u><u>4</u><u>)</u><u> </u><u>and</u><u> </u><u>(</u><u>6</u><u>,</u><u> </u><u>1</u><u>)</u>

• x(t) = 6t --- equation (a)

• y(t) = 3t - 2 --- equation (b)

→ From equation (a), make t the subject:

→ \: { \tt{x(t) = 6t }} \\  \\ → \: { \tt{t =  \frac{x(t)}{6} }}

• substitute for t in equation (b)

→ \: { \tt{y(t) =  3(\frac{x(t)}{6}) - 2 }} \\  \\ → \: { \tt{y(t) =  \frac{x(t)}{2} - 2 }}

• Assume t is 1:

→ \: { \tt{y =  \frac{x}{2}  - 2}} \\  \\ → \: { \boxed{ \tt{2y = x - 4}}}

• when x is zero, y is -4

→ \: { \tt{2y = 0 - 4 =  - 4}} \\

• when x is 6, y is 1

→ \: { \tt{2y = 6 - 4 = 2 }} \\ { \tt{y = 1}}

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