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2 years ago

Please solve this using like terms! 2(−14+r)−(−3r−5)

Mathematics

1 answer:

tia_tia [17]2 years ago

6 0

Answer:

5r-23

Step-by-step explanation:

multiple 2 with -14 and r

then subtract 2r - (-3) and -28 -(-5)

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Korvikt [17]

The second in the top row is this:
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2 years ago

(b) dy/dx = (x - y+ 1)^2

Elanso [62]

Substitute $v(x)=x-y(x)+1$ , so that

$\dfrac{\mathrm dv}{\mathrm dx}=1-\dfrac{\mathrm dy}{\mathrm dx}$

Then the resulting ODE in $v(x)$ is separable, with

$1-\dfrac{\mathrm dv}{\mathrm dx}=v^2\implies\dfrac{\mathrm dv}{1-v^2}=\mathrm dx$

On the left, we can split into partial fractions:

$\dfrac12\left(\dfrac1{1-v}+\dfrac1{1+v}\right)\mathrm dv=\mathrm dx$

Integrating both sides gives

$\dfrac{\ln|1-v|+\ln|1+v|}2=x+C$

$\dfrac12\ln|1-v^2|=x+C$

$1-v^2=e^{2x+C}$

$v=\pm\sqrt{1-Ce^{2x}}$

Now solve for $y(x)$ :

$x-y+1=\pm\sqrt{1-Ce^{2x}}$

$\boxed{y=x+1\pm\sqrt{1-Ce^{2x}}}$

3 0

3 years ago

Asap please and thank you

fgiga [73]

Answer:

<h2> x = 16 degrees</h2>

Step-by-step explanation:

1 and 3 are <u>vertical angles</u> so m∠1 = m∠3

(4x - 2)° = 62°

4x - 2 = 62

4x = 64

x = 16

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2 years ago

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Cerrena [4.2K]

Congruent because both angles are the same

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2 years ago

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BigorU [14]

Answer:

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Step-by-step explanation:

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8 0

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