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igomit [66]
3 years ago
14

Original price: ? Percent of discount: 25% Sale price: $45

Mathematics
2 answers:
My name is Ann [436]3 years ago
5 0

Answer:

Original price is 11.25

Step-by-step explanation:

Anna [14]3 years ago
3 0

Answer: 60

The percent of sale price is 100% - 25% = 75%

the original price is (45/75).100 = 60$

Step-by-step explanation:

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The length of a rectangle is one inch less than three times its width. If the perimeter of the rectangle is 118 inches, find the
IgorLugansk [536]
We can set up the width a X and, from the description the length would be 3X-1. The perimeter of a rectangle is determined by 2XL + 2Xw. Plugging into the equation 2(3X-1) + 2(X) = 118. Next distribute to get 6X-2 + 2X = 118. Combine like terms to get 8X = 120. Divide by 8 to get X = 15. The width is 15. The length is 3(15)-1 or 44. 88 +30 = 118
6 0
3 years ago
Solve: 9x-7≤28+4x;x€W​
Natasha_Volkova [10]

Answer:

z ≤ 7

Step-by-step explanation:

9x - 7 ≤ 28 + 4x

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4 0
3 years ago
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Triangle $ABC$ has a right angle at $B$. Legs $\overline{AB}$ and $\overline{CB}$ are extended past point $B$ to points $D$ and
Lisa [10]

Answer:

Given :

ABC is a right triangle in which ∠ABC = 90°,

Also, Legs AB and CB are extended past point B to points D and E,

Such that,

\angle EAC = \angle ACD = 90^{\circ}

To prove :

EB\times BD=AB\times BC

Proof :

In triangles AEC and EBA,

∠EAC= ∠ABE ( right angles )

∠CEA = ∠AEB ( common angles )

By AA similarity postulate,

\triangle AEC \sim \triangle EBA,

Similarly,

\triangle AEC \sim \triangle ABC

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Now, In triangles ADC and CBD,

∠ACD = ∠CBD ( right angles )

∠ADC= ∠BDC ( common angles )

By AA similarity postulate,

\triangle ADC \sim \triangle CBD,

Similarly,

\triangle ADC \sim \triangle ABC

\implies \triangle CBD\sim \triangle ABC-----(2)

From equations (1) and (2),

\triangle EBA\sim \triangle CBD

The corresponding sides of similar triangles are in same proportion,

\frac{EB}{BC}=\frac{AB}{BD}

\implies EB\times BD=AB\times BC

Hence, proved....

5 0
3 years ago
Solve for x. a) 10 b) 12 c) 13 d) 11
Over [174]

Answer:

A : 10

Step-by-step explanation:

4 0
3 years ago
Best answer gets brainliest
patriot [66]

Question below!

what do you need in order to construct in order to find a point/location that has the same distance away from 2 or more other points

Answer:

Hi, There! Mika-Chan I'm here to help! :)

<u><em>To find the distance from a point to a line, first find the perpendicular line passing through the point. Then using the Pythagorean theorem, find the distance from the original point to the point of intersection between the two lines.</em></u>

<u><em></em></u>

<u><em>Hope this Helps!</em></u>

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