SOLUTION IS
WE KNOW STANDARD EQUATION OF CIRCLE
+
=
where (a,b) is centre and r is radius of circle
now we have to find component of centre and radius
we know centre of circle is equidistance from end points of diameter
apply formula to find mid point of line( (x1+x2)/2,(y1+y2)/2) we get
((x-x)/2,(y-y)/2)=(0,0)
hence component of circle is (0,0)
now apply distance formula between (0,0)and (x,y)
we get
+
=
hence standard equation of circlre is =
+
=
+
Answer:
5 miles per hour
Step-by-step explanation:
all you have to do is divide 15 by 3 to get 5
Answer:
2r (1 + √3)
Step-by-step explanation:
Circle O₁ is tangent to AB. Let's call the point of intersection point D. If we draw a radius from the center O₁ to D, we know this forms a right angle.
△ABC is an equilateral triangle, so we know m∠A = 60°. If we draw a line from A to O₁, we know that bisects the angle, so m∠DAO₁ = 30°.
So △DAO₁ is a 30-60-90 triangle. We can find the length AD:
AD = r √3
Now on the other side, circle O₃ is tangent to AB. Let's call the point of intersection point E. We know it's the same triangle we found earlier, so:
EB = r √3
And finally, we can draw a rectangle connecting O₁, O₃, E, and D. The distance between O₁ and O₃ is 2r, so:
DE = 2r.
Therefore:
AB = r√3 + 2r + r√3
AB = 2r√3 + 2r
AB = 2r (1 + √3)
Here's a graph showing the steps. Hopefully this helps, let me know if you have questions!
desmos.com/calculator/hgaonfzxsm
Answer:
99 pages.
Step-by-step explanation:
First divide 165 by 5, to get 1/5th of the book. The answer is 33
Now, multiply 33 by 3 in order to get 3/5ths of the book.
You get 99 pages.
Answer:
Step-by-step explanation: o847434y3u3u44y4u5u5u5uu6