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4 years ago

Write using algebra.

Mathematics

2 answers:

ipn [44]4 years ago

7 0

D x 2= c so whatever Leo has Pete always has twice as much

lyudmila [28]4 years ago

6 0

D * 2
Pete has 2 times more than Leo
* = times ( fact)

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Percent of change 0.55 trees to 31 trees

Goryan [66]

31.55 this will be your answer

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4 years ago

The jogging track is 5/9 of a mile long. If Ashley jogged around it 4 times, how far did she run? A.4/9 B.20/9 C.9/4 D. 4 5/9

777dan777 [17]

Answer:

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4 years ago

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Without using a calculator, choose the statement that the best describes the value of 24. Help me please...

Viktor [21]

Answer:

Step-by-step explanation:

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3 years ago

The heights of a certain population of corn plants follow a normal distribution with mean 145 cm and stan- dard deviation 22 cm

Firdavs [7]

Answer with explanation:

Given : The heights of a certain population of corn plants follow a normal distribution with mean $\mu=145\ cm$ and standard deviation $\sigma=22\ cm$

a) Using formula $z=\dfrac{x-\mu}{\sigma}$ , the z-value corresponds to x= 135 will be

$z=\dfrac{135-145}{22}\approx-0.45$

At x= 155, $z=\dfrac{155-145}{22}\approx0.45$

The probability that plants are between 135 and 155 cm tall :-

$P(-0.45$

Hence, 34.73% of the plants are between 135 and 155 cm tall.

b) Sample size : n= 16

Using formula $z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}$ , the z-value corresponds to x= 135 will be

$z=\dfrac{135-145}{22}{\sqrt{16}}\approx-1.82$

At x= 155, $z=\dfrac{155-145}{22}{\sqrt{16}}\approx1.82$

The probability that plants are between 135 and 155 cm tall :-

$P(-1.82$

Hence,The percentage of the samples would the sample mean height be between 135 and 155 cm.= 93.12%

4 0

3 years ago

MS. Kitts works at a music store. Last week she sold 6 more than 3 times the number of CDs that she sold this week. Ms. Kitts so

puteri [66]

x - 3y = 6 and x + y = 110 represents the system of equations used to find x, the number of CDs she sold last week, and y, the number of CDs she sold this week

number of CDs Kitts sold last week "x" is 84 and number of CDs she sold this week "y" is 26

<h3><u>Solution:</u></h3>

Let "x" be the number of CDs Kitts sold last week

Let "y" be the number of CDs she sold this week

<em><u>Given that Last week she sold 6 more than 3 times the number of CDs that she sold this week</u></em>

Number of CDs Kitts sold last week = 6 + 3(number of CDs that she sold this week)

x = 6 + 3y ----- eqn 1

x - 3y = 6 ------- eqn 2

<em><u>Given that Ms. Kitts sold a total of 110 CDs over the 2 weeks</u></em>

Number of CDs Kitts sold last week + number of CDs she sold this week = 110

x + y = 110 ----- eqn 3

Thus eqn 2 and eqn 3 represents the system of equations used to find x, the number of CDs she sold last week, and y, the number of CDs she sold this week

<em><u>Let us solve the above equations to find values of "x" and "y"</u></em>

Substitute eqn 1 in eqn 3

6 + 3y + y = 110

6 + 4y = 110

4y = 104

From eqn 3,

x + 26 = 110

x = 110 - 26 = 84

Thus number of CDs Kitts sold last week = x = 84

Number of CDs she sold this week = y = 26

6 0

3 years ago