All categories

4 years ago

Convert 8 ounces to pounds.

Mathematics

2 answers:

BigorU [14]4 years ago

7 0

Answer:

8 ounces=0.5 pound

Step-by-step explanation:

Formula: divide the mass value by 16.

LenKa [72]4 years ago

3 0

Answer:

Formula: divide the mass value by 16.

Step-by-step explanation:

You might be interested in

Help guys show your solution

irinina [24]

Answer:

Profit = $\frac{80p+170}{p}$

Step-by-step explanation:

Cost of the Yield = $\frac{100p+200}{p}$

Cost of the labour = $\frac{10p+50}{p}$

Cost of the fertilisers = $\frac{10p - 20}{p}$

Total expenses = $\frac{10p + 50}{p} + \frac{10p - 20}{p} = \frac{20p + 30}{p}$

Profit = Cost of yield - Total expenses

$=>\frac{100p + 200}{p} - \frac{20p + 30}{p}$

$=> \frac{80p + 170}{p}$

3 0

3 years ago

Question 2 (4 points)

madreJ [45]

I believe the correct answer is B

3 0

3 years ago

Read 2 more answers

g The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control

Rudiy27

Answer:

0.1426 = 14.26% probability that at least one of the births results in a defect.

Step-by-step explanation:

For each birth, there are only two possible outcomes. Either it results in a defect, or it does not. The probability that a birth results in a defect is independent of any other birth. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC).

This means that $p = \frac{1}{33}$

A local hospital randomly selects five births.

This means that $n = 5$

What is the probability that at least one of the births results in a defect?

This is:

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(\frac{1}{33})^{0}.(\frac{32}{33})^{5} = 0.8574$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.8574 = 0.1426$

0.1426 = 14.26% probability that at least one of the births results in a defect.

4 0

3 years ago

A box contains 7 yellow, 5 blue, and 4 red balls. Three balls are drawn at random. Find the probability that:

Digiron [165]

Answer:

a) 7/80 = 0.0875

b) 3/16 = 0.1875

c) 1/4 = 0.2500

Step-by-step explanation:

There are a total of 16 balls. 3 are selected. There are ₁₆C₃ possible combinations.

a) If all 3 balls are the same color, they are either all yellow OR all blue OR all red.

The number of ways of choosing 3 yellow balls from 7 is ₇C₃.

The number of ways of choosing 3 blue balls from 5 is ₅C₃.

The number of ways of choosing 3 red balls from 4 is ₄C₃.

The total probability is:

P = (₇C₃ + ₅C₃ + ₄C₃) / ₁₆C₃

P = (35 + 10 + 4) / 560

P = 49 / 560

P = 7 / 80

P = 0.0875

b) The number of ways of choosing 2 yellow balls from 7 is ₇C₂.

The number of ways of choosing 1 blue ball from 5 is ₅C₁.

The probability of both is:

P = ₇C₂ ₅C₁ / ₁₆C₃

P = 21 × 5 / 560

P = 105 / 560

P = 3 / 16

P = 0.1875

c) If all 3 balls are different colors, then there is exactly 1 yellow, 1 blue, and 1 red.

The number of ways of choosing 1 yellow ball from 7 is ₇C₁.

The number of ways of choosing 1 blue ball from 5 is ₅C₁.

The number of ways of choosing 1 red ball from 4 is ₄C₁.

The probability of all events is:

P = ₇C₁ ₅C₁ ₄C₁ / ₁₆C₃

P = 7 × 5 × 4 / 560

P = 140 / 560

P = 1 / 4

P = 0.2500

3 0

3 years ago

What is this equation 4(3+5)- 3.9*2<br> THIS ISN´T A DECIMAL ITS A MIDDLE DOT

vredina [299]

Answer:

The answer is letter 'J'

Step-by-step explanation:

4(3+5) - 3 x 9^2

4(8) - 3 x 9^2 ← 9 x 9 = 81

16 - 3 x 9^2

16 - 3 x 81

13 x 81

1,053

4 0

3 years ago