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xenn [34]
3 years ago
5

Ming's recipe for sweet tea calls 4 teaspoon of sugar. If Ming wants to make the tea 25% less sweet, how much less sugar should

he use??​
PLEASE HELP AND EXPLAINN​
Mathematics
1 answer:
Paha777 [63]3 years ago
4 0

Answer:

He needs 3 cups of sugar, so he should use 1 cup less

Step-by-step explanation:

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Please help me find the area of this figure
Harman [31]

Answer:

=51.63 m^2

Step-by-step explanation:

First find the area of the triangle

A = 1/2 bh = 1/2(3) * 5 = 7.5

Then find the area of the rectangle

A = l*w = 5*6 = 30

Then find the area of the semi circle, which is 1/2 the area of the circle

The diameter is 6 so the radius is 3

A = 1/2  pi r^2 = 1/2 (3.14) (3) ^2 = 14.13

Add the areas together for the total area

7.5+30+14.13

=51.63

5 0
3 years ago
Which graph represents the given exponential function?
VikaD [51]

Answer:

Hey I'm sorry I didn't get to answer your question it's just that I need the points because I don't have enough to get help with my question. I hope you get the answer that you need for you question. Good Luck :)

Step-by-step explanation:

7 0
3 years ago
You play two games against the same opponent. The probability you win the first game is 0.4. If you win the first game, the prob
Ilia_Sergeevich [38]

Answer:

a) No

b) 42%

c) 8%

d) X               0                 1                2

   P(X)           42%            50%         8%

e) 0.62

Step-by-step explanation:

a) No, the two games are not independent because the the probability you win the second game is dependent on the probability that you win or lose the second game.

b) P(lose first game) = 1 - P(win first game) = 1 - 0.4 = 0.6

P(lose second game) = 1 - P(win second game) = 1 - 0.3 = 0.7

P(lose both games) = P(lose first game)  × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

c)   P(win first game)  = 0.4

P(win second game) = 0.2

P(win both games) = P(win first game)  × P(win second game) = 0.4 × 0.2 = 0.08 = 8%

d) X               0                 1                2

   P(X)           42%            50%         8%

P(X = 0)  =  P(lose both games) = P(lose first game)  × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

P(X = 1) = [ P(lose first game)  × P(win second game)] + [ P(win first game)  × P(lose second game)] = ( 0.6 × 0.3) + (0.4 × 0.8) = 0.18 + 0.32 = 0.5 = 50%

e) The expected value  \mu=\Sigma}xP(x)= (0*0.42)+(1*0.5)+(2*0.08)=0.66

f) Variance \sigma^2=\Sigma(x-\mu^2)p(x)= (0-0.66)^2*0.42+ (1-0.66)^2*0.5+ (2-0.66)^2*0.08=0.3844

Standard deviation \sigma=\sqrt{variance} = \sqrt{0.3844}=0.62

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=18%20310%20%E2%88%92%209%20910%20%3D" id="TexFormula1" title="18 310 &minus; 9 910 =" alt="18
Marta_Voda [28]

Answer:

8400

Step-by-step explanation:

18310 - 9910

= 8400

Hope it helps you!!

#IndianMurga(. ❛ ᴗ ❛.)

3 0
3 years ago
There was 1500ml of orange juice in the carton. Molly used 1/4litre at breakfast. How much orange juice was left in the carton.?
emmasim [6.3K]

Answer:

1250ml

Step-by-step explanation:

1/4litre=250ml

1500-250

5 0
3 years ago
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