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makvit [3.9K]
2 years ago
6

The following are true about a square of a binomial except

Mathematics
2 answers:
-BARSIC- [3]2 years ago
8 0

Answer:

B. ITS FIRST TERM IS A PERFECT SQUARED ITS MIDDLE TERM IS ALWAYS NEGATIVE.

pishuonlain [190]2 years ago
6 0

Answer:

D. It's middle term is always negative.

Step-by-step explanation:

A square of a binomial (perfect square), means that the two binomial terms are the same. Therefore, both terms will include either a double positive (which would result in a positive answer), or a double negative, (which, by the law of multiplying double negatives, would result in a positive answer).

Therefore, D will be the correct "incorrect" answer.

~

You might be interested in
Verify each trigonometric equation by substituting identities to match the right hand side of the equation to the left hand side
lorasvet [3.4K]

Answer:

Step-by-step explanation:

1.

cot x sec⁴ x = cot x+2 tan x +tan³x

L.H.S = cot x sec⁴x

       =cot x (sec²x)²

       =cot x (1+tan²x)²     [ ∵ sec²x=1+tan²x]

       =  cot x(1+ 2 tan²x +tan⁴x)

       =cot x+ 2 cot x tan²x+cot x tan⁴x

        =cot x +2 tan x + tan³x        [ ∵cot x tan x =\frac{ \textrm{tan x }}{\textrm{tan x}} =1]

       =R.H.S

2.

(sin x)(tan x cos x - cot x cos x)=1-2 cos²x

 L.H.S =(sin x)(tan x cos x - cot x cos x)

          = sin x tan x cos x - sin x cot x cos x

           =\textrm{sin x cos x }\times\frac{\textrm{sin x}}{\textrm{cos x} } - \textrm{sinx}\times\frac{\textrm{cos x}}{\textrm{sin x}}\times \textrm{cos x}

           = sin²x -cos²x

           =1-cos²x-cos²x

           =1-2 cos²x

           =R.H.S

         

3.

1+ sec²x sin²x =sec²x

L.H.S =1+ sec²x sin²x

         =1+\frac{{sin^2x}}{cos^2x}                       [\textrm{sec x}=\frac{1}{\textrm{cos x}}]

         =1+tan²x                        [\frac{\textrm{sin x}}{\textrm{cos x}} = \textrm{tan x}]

         =sec²x

        =R.H.S

4.

\frac{\textrm{sinx}}{\textrm{1-cos x}} +\frac{\textrm{sinx}}{\textrm{1+cos x}} = \textrm{2 csc x}

L.H.S=\frac{\textrm{sinx}}{\textrm{1-cos x}} +\frac{\textrm{sinx}}{\textrm{1+cos x}}

       =\frac{\textrm{sinx(1+cos x)+{\textrm{sinx(1-cos x)}}}}{\textrm{(1-cos x)\textrm{(1+cos x})}}

      =\frac{\textrm{sinx+sin xcos x+{\textrm{sinx-sin xcos x}}}}{{(1-cos ^2x)}}

     =\frac{\textrm{2sin x}}{sin^2 x}

      = 2 csc x

    = R.H.S

5.

-tan²x + sec²x=1

L.H.S=-tan²x + sec²x

        = sec²x-tan²x

        =\frac{1}{cos^2x} -\frac{sin^2x}{cos^2x}

        =\frac{1- sin^2x}{cos^2x}

        =\frac{cos^2x}{cos^2x}

        =1

     

       

8 0
3 years ago
Apples cost $0.75 per pound and bananas cost $1.05 per pound.
dedylja [7]

Answer:

The baker bought 8 pounds of apples and 4 pounds of bananas.

Step-by-step explanation:

a+b=12.

0.75a+1.05b=10.20

First, multiply 2 my 10.

75a+105b=1020.

Then multiply 1 by 75.

75a+75b=900.

Then subtract.

75a+105b=1020

75a+75b=900.

75a-75a+105b-75b=1020-900

30b=120

b=4

Substitute into (1)

a+4=12

a=8.

Hope this helps :)

3 0
3 years ago
Someone help pls!!!!!!!!!!!
Gemiola [76]
The answer is no question for you lol
7 0
3 years ago
The midpoint of segment AB is (-7, 10) and endpoint A is located at (3, -1). Find the other endpoint B. Show all work.
dusya [7]

Answer:

B(-17,21)

Step-by-step explanation:

The midpoint of two points is the average of the x coordinates and the average of the y coordinates.

Given

A(3, -1)

and we let the other end point B be B(x,y)

and midpoint is (-7,10)

So, the average of 3 and x is -7, and

the average of -1 and y is 10

We can solve for x first:

\frac{3+x}{2}=-7\\3+x=2*-7\\3+x=-14\\x=-14-3\\x=-17

and now solving for y:

\frac{-1+y}{2}=10\\-1+y=2*10\\-1+y=20\\y=20+1\\y=21

So, the other point B is:

B(-17,21)

6 0
3 years ago
The results of a survey of 43 students and the foreign language they are studying are shown in the two-way frequency table.
babunello [35]
Since 5 out of 43 people take chinese, it's 5/43 which is the same as 0.116 which means 11,6%

I hope this was helpful! Tell me if it's unclear!
4 0
3 years ago
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