Screenshot down below math question

On his first day of school, Kareem found the high temperature in degrees Fahrenheit to be 76.1°. He plans to use the function C

Naddik [55]

Answer: the temperature of 76.1 degrees Fahrenheit converted to degrees Celsius

Step-by-step explanation:

5 0

3 years ago

150 parents were surveyed. 26% said that the kids were noddy and 70% said their kids were nice. How many parents didn't answer w

alexandr1967 [171]

Answer:

The parents who didn't answer with either naughty and nice are 6.

Step-by-step explanation:

Given:

150 parents were surveyed. 26% said that the kids were naughty and 70% said their kids were nice.

Now, to find parents who didn't answer with either naughty and nice.

So, as given in question:

70% said that their kids are naughty.

26% said that their kids are nice.

So, to get the percentage of parents who didn't answer we subtract.

Thus, the percentage of parents who didn't answer with either naughty and nice:

100% - (70% + 26%)

100% - 96% = 4%.

Hence, 4% of parents didn't answer.

Now, to get how many parents didn't answer we calculate the percentage of the total who didn't answer:

Total parents surveyed = 150.

Parents who didn't answer = 4% of the total parents surveyed.

$Parents\ who\ didn't\ answer = 4\% of 150.$

$Parents\ who\ didn't\ answer = \frac{4}{100}\times 150.$

$Parents\ who\ didn't\ answer = \frac{600}{100}.$

$Parents\ who\ didn't\ answer = 6.$

Therefore, the parents who didn't answer with either naughty and nice are 6.

8 0

3 years ago

4.20. According to a report released by the National Center for Health Statistics, 51% of U.S. households has only cell phones (

Sergeu [11.5K]

Answer:

The probability that the household has only cell phones and has high-speed Internet is 0.408

Step-by-step explanation:

Let A be the event that represents U.S. households has only cell phones

Let B be the event that represents U.S. households have high-speed Internet.

We are given that 51% of U.S. households has only cell phones

P(A)=0.51

We are given that 70% of the U.S. households have high-speed Internet.

P(B)=0.7

We are given that U.S. households having only cell phones, 80% have high-speed Internet. A U.S household is randomly selected.

P(B|A)=0.8

$\frac{P(A\capB)}{P(A)}=0.8\\P(A\capB)=0.8 \times P(A)\\P(A\capB)=0.8 \times 0.51\\P(A\capB)=0.408$

Hence the probability that the household has only cell phones and has high-speed Internet is 0.408

7 0

3 years ago

You purchase a car using a $20,000 loan with a 5% simple interest rate.

hammer [34]

Simple interest = Cost Price + (Interest Percentage of Cost Price × number of years or months we are paying off)

a) SI = £20 000 + (5% of £20 000 × 4)
SI = £20 000 + (£1000 × 4)
SI = £20 000 + £4000 = £24 000

b) SI = £20 000 + (5% of £20 000 × 3)
SI = £20 000 + (£1000 × 3)
SI = £20 000 + £3000 = £23 000

£24 000 - £23 000 = £1000 that you saved!

3 0

3 years ago

For s=5 and t=8, 3st²-s²: 3st²-s² =

melomori [17]

Step-by-step explanation:

Given,

s=5

t=8

solution,

= 3st² - s²

= 3*5*8² - 5²

= 3*5*64 - 25

= 960 - 25

= 935

8 0

2 years ago