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Alecsey [184]
3 years ago
7

Triangle ABC with vertices A(9, 13), B(12, 11), and C(8,7);

Mathematics
1 answer:
umka21 [38]3 years ago
3 0

When a triangle is dilated, the size of the triangle changes.

<em>The image of </em>\triangle A'B'C'<em> are:</em>

A' = (7,12)

B' = (13,8)

C' =(5,0)

We have:

A = (9,13)

B = (12,11)

C = (8,7)

k = 2

Start by multiplying the scale factor by the coordinates of \triangle ABC

A = (9,13) \times 2

A = (18,26)

B = (12,11) \times 2

B = (24,22)

C =(8,7) \times 2

C =(16,14)

Subtract the center of dilation from the above coordinates

A' = (18,26) - (11,14)

A' = (18-11,26-14)

A' = (7,12)

B' = (24,22) - (11,14)

B' = (24-11,22-14)

B' = (13,8)

C' =(16,14) - (11,14)

C' =(16 - 11,14 - 14)

C' =(5,0)

Hence, the image of \triangle A'B'C' are:

A' = (7,12)

B' = (13,8)

C' =(5,0)

Read more about dilations at:

brainly.com/question/13176891

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