Question

Triangle ABC with vertices A(9, 13), B(12, 11), and C(8,7);

Answer 1

When a triangle is dilated, the size of the triangle changes.

The image of $\triangle A'B'C'$ are:

$A' = (7,12)$

$B' = (13,8)$

$C' =(5,0)$

We have:

$A = (9,13)$

$B = (12,11)$

$C = (8,7)$

$k = 2$

Start by multiplying the scale factor by the coordinates of $\triangle ABC$

$A = (9,13) \times 2$

$A = (18,26)$

$B = (12,11) \times 2$

$B = (24,22)$

$C =(8,7) \times 2$

$C =(16,14)$

Subtract the center of dilation from the above coordinates

$A' = (18,26) - (11,14)$

$A' = (18-11,26-14)$

$A' = (7,12)$

$B' = (24,22) - (11,14)$

$B' = (24-11,22-14)$

$B' = (13,8)$

$C' =(16,14) - (11,14)$

$C' =(16 - 11,14 - 14)$

$C' =(5,0)$

Hence, the image of $\triangle A'B'C'$ are:

$A' = (7,12)$

$B' = (13,8)$

$C' =(5,0)$

Read more about dilations at:

brainly.com/question/13176891