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Answer:
point (5, 5) is in Quadrant: I (1)
point (3, –2) is in Quadrant: IV (4)
The point (–4, –4) is in Quadrant: III (3)
Step-by-step explanation:
Since it is perpendicular to y=3x-1, the slope must be a negative reciprocal.
there the slope of the perpendicular line is
So now we have,
To find b, we use the point that the line passes through and substitute it to the y and x values.
which would give us b=5/3
Therefore, the equation of the line is
there the slope of the perpendicular line is
So now we have,
To find b, we use the point that the line passes through and substitute it to the y and x values.
which would give us b=5/3
Therefore, the equation of the line is