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Alex73 [517]
3 years ago
8

A bowl contains

Mathematics
2 answers:
Colt1911 [192]3 years ago
8 0

Answer:

\frac{1}{2} n(n - 1) =  \frac{12}{2}  = 6

(Apple, Banana), ( Apple, Orange), (Apple, Peach),

(Banana, Orange), (Banana, Peach),

(Orange, Peach)

12345 [234]3 years ago
5 0
1 apple + 1 banana
1 apple + 1 orange
1 apple + 1 peach
1 banana + 1 apple
1 banana + 1 orange
1 banana + 1 peach
1 orange + 1 apple
1 orange + 1 banana
1 orange + 1 peach
1 peach + 1 apple
1 peach + 1 orange

11 combinations of food

Hope this helped
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PLZ HELP I AM GONNA FAIL JUST EXPLAIN WHAT TO DO ​
Alexxandr [17]
A number cube is a die (singular for dice). List all of the possible outcomes of a die (list numbers of 1 to 6), and next to those numbers, determine if they are even or odd.
8 0
3 years ago
Find d for the arithmetic series with S17=-170 and a1=2
Irina18 [472]
So, we know the sum of the first 17 terms is -170, thus S₁₇ = -170, and we also know the first term is 2, well

\bf \textit{ sum of a finite arithmetic sequence}\\\\
S_n=\cfrac{n(a_1+a_n)}{2}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
----------\\
n=17\\
S_{17}=-170\\
a_1=2
\end{cases}
\\\\\\
-170=\cfrac{17(2+a_{17})}{2}\implies \cfrac{-170}{17}=\cfrac{(2+a_{17})}{2}
\\\\\\
-10=\cfrac{(2+a_{17})}{2}\implies -20=2+a_{17}\implies -22=a_{17}

well, since the 17th term is that much, let's check what "d" is then anyway,

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
n=17\\
a_{17}=-22\\
a_1=2
\end{cases}
\\\\\\
-22=2+(17-1)d\implies -22=2+16d\implies -24=16d
\\\\\\
\cfrac{-24}{16}=d\implies -\cfrac{3}{2}=d
6 0
3 years ago
When the solutions are going to be complex, which methods can be used to solve quadratic equations?
yKpoI14uk [10]
You could complete the square to state the vertex. 
You could use the quadratic equation to find the roots (which are complex). 

Try an example that will require both.

y = x^2 + 2x + 5

Step One
Get the graph. That's included below.

Step Two
Provide the steps for completing the square.
Note: we should get (-1,4)

y= (x^2 +2x ) + 5
y = (x^2 +2x + 1) + 5 - 1
y = (x +1)^2 + 4

The vertex is at (-1,4)

Step Three
Find the roots. Use the quadratic equation. Note that the graph shows us that the equation never crosses or touches the x axis. The roots are complex.

\text{x = }\dfrac{ -b \pm \sqrt{b^{2} - 4ac } }{2a}

a = 1
b = 2
c = 5

\text{x = }\dfrac{ -2 \pm \sqrt{2^{2} - 4*1*5 } }{2}
\text{x = }\dfrac{ -2 \pm \sqrt{4 - 20 } }{2}
\text{x = }\dfrac{ -2 \pm \sqrt{-16 } }{2}
\text{x = }\dfrac{ -2 \pm 4i }{2}
x = -1 +/- 2i

x1 = -1 + 2i
x2 = -1 - 2i And we are done.


7 0
3 years ago
I don't know how to do it I'm completely lost I asked my mom and brother and even Googled it NOTHING!!! Can you please help me??
telo118 [61]
31/18 is the answer.
To solve, find the common denominator. In this case, I used 54. You need to multiply each fraction to get 54 on the denominator of both.
4 0
3 years ago
Read 2 more answers
A car enters an interstate highway 20 mi north of a city. The car travels north at an average speed of 58 mph. Which equation mo
alexira [117]
A. 20H + 58 is your answer
3 0
3 years ago
Read 2 more answers
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