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2 years ago

Find the size of the angle marked a and b on the diagram

Mathematics

2 answers:

castortr0y [4]2 years ago

8 0

Answer:

Step-by-step explanation:

We know:

Angles in a triangle sum to 180°.

Therefore:

52° + 90° + b = 180°

142° + b = 180° |-142°

<em>(look at the picture)</em>

a + b = 90° ⇒ a + 38° = 90° |-38°

Angles 52° and a, are alternate interior angles. Therefore they are congruent.

Lana71 [14]2 years ago

5 0

Answer:

Step-by-step explanation:

we know that the total angles around the big triangle are 180° so, we know the right angle is 90° and we are told that one of the angles is 52° so just find the last angle by

180 = 90 + 52 + X

180 - 90 - 52 = X

38 = X

b = 38°

a = 52°

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Aiden wrote a riddle: Five less than 1/5 times a number is the same as the sume of the number and 1/3. Find the number.

Brrunno [24]

The number is -6.67

<em><u>Solution:</u></em>

Let "n" be the number

From given,

$\text{ Five less than 1/5 times a number } = \frac{1}{5}n - 5 = \frac{5}{n} - 5$

$\text{Sum of number and 1/3 } = n + \frac{1}{3} =\frac{3n+1}{3}$

Given that,

Five less than 1/5 times a number is the same as the sum of the number and 1/3

Therefore, we get,

$\frac{n}{5} - 5 = n + \frac{1}{3}\\\\Simplify\ the\ expression\\\\n - 25 = 5(n + \frac{1}{3})\\\\n - 25 = 5n + \frac{5}{3}\\\\n - 25 = \frac{15n + 5}{3}\\\\3n - 75 = 15n + 5\\\\12n = -80\\\\n = -6.67$

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3 years ago

The circumference of the ellipse approximate. Which equation is the result of solving the formula of the circumference for b?

Serhud [2]

Answer:

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

Step-by-step explanation:

Given - The circumference of the ellipse approximated by $C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }$ where 2a and 2b are the lengths of 2 the axes of the ellipse.

To find - Which equation is the result of solving the formula of the circumference for b ?

Solution -

$C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }\\\frac{C}{2\pi } = \sqrt{\frac{a^{2} + b^{2} }{2} }$

Squaring Both sides, we get

$[\frac{C}{2\pi }]^{2} = [\sqrt{\frac{a^{2} + b^{2} }{2} }]^{2} \\\frac{C^{2} }{(2\pi)^{2} } = {\frac{a^{2} + b^{2} }{2} }\\2\frac{C^{2} }{4(\pi)^{2} } = {{a^{2} + b^{2} }$

$\frac{C^{2} }{2(\pi )^{2} } = a^{2} + b^{2} \\\frac{C^{2} }{2(\pi )^{2} } - a^{2} = b^{2} \\\sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}} = b$

∴ we get

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

8 0

3 years ago