Ask question

Ask question

All categories

3 years ago

14

a student throws a rock horizontally from the edge of a cliff that is 20 m high. the rock has an initial speed of 10 m/s. if air

resistance is negligible, the distance from the base of the cliff to where the rock hits the level ground below the cliff is most nearly

1 answer:

serg [7]3 years ago

6 0

Answer:

40m

Explanation:

u=10m/s, h=20m, g=?, s=h, v=0

solve for g first

v²=u²+2gs

0=10²+2×g×20

0=100+40g

-100=40g

g=-2.5m/s²

solve for time t

v=u+gt

0=10+(-2.5t)

-10=-2.5t

divide both side by -2.5

-10/-2.5=t

t=4s

lastly, solve for x(distance)

x=ut+1/2gt²

x=10×4+1/2×2.5×16

x=40+(2.5×8)

x=40+20=60

then subtract the d1(initial) from d2(final) distance

x=60-20=40m

You might be interested in

Last Christmas I gave you my heart but the very next day you gave it away this year to save me from tears I’ll give it to someon

Ahat [919]

Answer:

a little late but ok xD

LAST CHRISTMAS I GAVE U MY HEARTT!!!

5 0

3 years ago

Read 2 more answers

Which element has the highest melting point tantalum rhenium osmium hafnium.

blagie [28]

Answer:

Number 1

Explanation:

4 0

3 years ago

What are the coefficients needed to balance this chemical reaction to show that matter is conserved? fe + cl2 → fecl3

motikmotik

Let a, b, and c be the coefficients in the balanced reaction:

a Fe + b Cl₂ → c FeCl₃

Count the atoms that show up among the reactants and products. They should be equal on both sides:

Fe : a = c

Cl : 2b = 3c

Let c = 2. Then a = 2 and 2b = 6, so b = 3.

Then the balanced reaction is

2 Fe + 3 Cl₂ → 2 FeCl₃

5 0

3 years ago

company manufactured six television sets on a given day, and these TV sets were inspected for being good or defective. The resul

lana [24]

Sampling distribution involves the proportions of a data element in a given sample.

<em>The proportion of Good TV set is 0.67</em>
<em>The number of ways of selecting 5 from 6 TV sets is 6</em>
<em>The number of ways of selecting 4 from 6 TV sets is 15</em>

<em />

Given

$n = 6$

Sample Space = Good, Good, Defective, Defective, Good, Good

<u>(a) Proportion that are good</u>

From the sample space, we have:

$Good = 4$

So, the proportion (p) that are good are:

$p = \frac{Good}{n}$

$p = \frac{4}{6}$

$p = 0.67$

<u>(b) Ways to select 5 samples (without replacement)</u>

This is calculated using:

$^nC_r = \frac{n!}{(n - r)!r!}$

Where

$r = 5$

So, we have:

$^6C_5 = \frac{6!}{(6 - 5)!5!}$

$^6C_5 = \frac{6!}{1!5!}$

$^6C_5 = \frac{6 \times 5!}{1 \times 5!}$

$^6C_5 = \frac{6}{1}$

$^6C_5 = 6$

Hence, there are 6 ways

<u>(c) All possible sample space of 4</u>

First, we calculate the number of ways to select 4.

This is calculated using:

$^nC_r = \frac{n!}{(n - r)!r!}$

Where

$r = 4$

So, we have:

$^6C_4 = \frac{6!}{(6 - 4)!4!}$

$^6C_4 = \frac{6!}{2!4!}$

$^6C_4 = \frac{6 \times 5 \times 4}{2 \times 1 \times 4!}$

$^6C_4 = \frac{30}{2}$

$^6C_4 = 15$

So, the table is as follows:

$\left[\begin{array}{ccc}TV&Good&Proportion\\1,2,3,4&2&0.5&2,3,4,5&2&0.5&3,4,5,6&2&0.5\\4,5,6,1&3&0.75&5,6,1,2&4&1&6,1,2,3&3&0.75\\1,2,3,5&3&0.75&3,5,6,2&3&0.75&1,3,4,5&2&0.5\\1,3,4,6&2&0.5&1,4,5,2&3&0.75&2,4,6,1&3&0.75\\2,4,6,3&2&0.5&2,4,6,5&3&0.75&3,5,6,1&3&0.75\end{array}\right]$

The proportion column is calculated by dividing the number of Good TVs by the total selected (4) i.e.

$p = \frac{Good}{n}$

<u>(d) The sampling distribution</u>

In (a), we have:

$p = 0.67$ --- proportion of Good TV

The sampling error is calculated as follows:

$SE_n = |p - p_n|$

So, we have:

$\left[\begin{array}{ccc}TV&Good&SE\\1,2,3,4&2&0.17&2,3,4,5&2&0.17&3,4,5,6&2&0.17\\4,5,6,1&3&0.08&5,6,1,2&4&0.33&6,1,2,3&3&0.08\\1,2,3,5&3&0.08&3,5,6,2&3&0.08&1,3,4,5&2&0.17\\1,3,4,6&2&0.17&1,4,5,2&3&0.08&2,4,6,1&3&0.08\\2,4,6,3&2&0.17&2,4,6,5&3&0.08&3,5,6,1&3&0.08\end{array}\right]$

Read more about sampling distributions at:

brainly.com/question/10554762

3 0

3 years ago

Which of the following describes the zeroes of the graph of f(x) = 3x6 30x5 75x4?.

lozanna [386]

Answer:

Explanation:

f(x) = 3x6 30x5 75x4?.

6 0

3 years ago