a student throws a rock horizontally from the edge of a cliff that is 20 m high. the rock has an initial speed of 10 m/s. if air resistance is negligible, the distance from the base of the cliff to where the rock hits the level ground below the cliff is most nearly
1 answer:
Answer:
40m
Explanation:
u=10m/s, h=20m, g=?, s=h, v=0
solve for g first
v²=u²+2gs
0=10²+2×g×20
0=100+40g
-100=40g
g=-2.5m/s²
solve for time t
v=u+gt
0=10+(-2.5t)
-10=-2.5t
divide both side by -2.5
-10/-2.5=t
t=4s
lastly, solve for x(distance)
x=ut+1/2gt²
x=10×4+1/2×2.5×16
x=40+(2.5×8)
x=40+20=60
then subtract the d1(initial) from d2(final) distance
x=60-20=40m
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